ruby中的数组更新

Question

给出两个数组：

s1 = ["Arun#2#very good shop","Mani#4#i am very glad to meet you sir.","Anu#2#not bad"]
s2 = ["first","second","third"]

我想要一个新的数组s3，如：

s3 = ["Arun#2#very good shop#first","Mani#4#i am very glad to meet you sir#second.","Anu#2#not bad#third"]

Answer 1

s3 = s1.zip(s2).map{ |x| x.join('#')}
=> ["Arun#2#very good shop#first", "Mani#4#i am very glad to meet you sir.#second", "Anu#2#not bad#third"]

Answer 2

试试这个：

> s3 = [s1,s2].transpose.map{|a| a.join("#")}
 => ["Arun#2#very good shop#first", "Mani#4#i am very glad to meet you sir.#second", "Anu#2#not bad#third"]

注意：如果两个数组具有相同数量的元素，这将有效。

替代选项：这适用于两个数组中的任意数量的元素

> s1.zip(["#"].cycle, s2).map(&:join)
 => ["Arun#2#very good shop#first", "Mani#4#i am very glad to meet you sir.#second", "Anu#2#not bad#third"]

Answer 3

假设您想在s2后的相应索引处追加s1到#的元素：

s3 = []
s1.each_with_index{|a, i| s3 << a + "#" + s2[i].to_s}
s3
# => ["Arun#2#very good shop#first", "Mani#4#i am very glad to meet you sir.#second", "Anu#2#not bad#third"]