在apex中通过sql命令获取报告后，我想存储与选中的复选框对应的变量sid,serial#的数据。之后我必须在顶点本身执行alter system kill session 'sid,serial#'
答案 0 :(得分：0)
您好我会在skillbuilders教程中向您展示this使用的方法，该方法基于collections
该方法包括四个步骤，其目的是对集合而不是从一组表格进行报告。我将对所有步骤进行说明，但我强烈建议您在上面的链接中查看视频，了解有关代码的具体详情。
首先您需要使用您的信息创建集合（并将其命名为） 想要在您的报表上显示，为此您将使用查询本身创建一个字符串，然后绑定您可能（或可能不需要）的变量。这是您的收藏模板，请记住，此模板需要根据您的方案进行调整。 在您的情况下，您最感兴趣的是项目＃47和＃50，这是状态字段（47）和复选框字段（50）。
DECLARE
l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
l_bind_names APEX_APPLICATION_GLOBAL.VC_ARR2;
l_bind_values APEX_APPLICATION_GLOBAL.VC_ARR2;
l_query VARCHAR2(32767);
BEGIN
l_collection_name := 'REPLACE_NAME';
IF apex_collection.collection_exists(l_collection_name)
THEN
apex_collection.delete_collection(
p_collection_name => l_collection_name
);
END IF;
--Query to initialize collection
--Do not reorder columns later as that could break the values in the tabular form (reorder in report)
l_query :=
'SELECT col_1, ' --c001 => f01
|| ' col_2, ' --c002 => f02
|| ' col_3, ' --c003 => f03
|| ' col_4, ' --c004 => f04
|| ' col_5, ' --c005 => f05
|| ' NULL, ' --c006 => f06
|| ' NULL, ' --c007 => f07
|| ' NULL, ' --c008 => f08
|| ' NULL, ' --c009 => f09
|| ' NULL, ' --c010 => f10
|| ' NULL, ' --c011 => f11
|| ' NULL, ' --c012 => f12
|| ' NULL, ' --c013 => f13
|| ' NULL, ' --c014 => f14
|| ' NULL, ' --c015 => f15
|| ' NULL, ' --c016 => f16
|| ' NULL, ' --c017 => f17
|| ' NULL, ' --c018 => f18
|| ' NULL, ' --c019 => f19
|| ' NULL, ' --c020 => f20
|| ' NULL, ' --c021 => f21
|| ' NULL, ' --c022 => f22
|| ' NULL, ' --c023 => f23
|| ' NULL, ' --c024 => f24
|| ' NULL, ' --c025 => f25
|| ' NULL, ' --c026 => f26
|| ' NULL, ' --c027 => f27
|| ' NULL, ' --c028 => f28
|| ' NULL, ' --c029 => f29
|| ' NULL, ' --c030 => f30
|| ' NULL, ' --c031 => f31
|| ' NULL, ' --c032 => f32
|| ' NULL, ' --c033 => f33
|| ' NULL, ' --c034 => f34
|| ' NULL, ' --c035 => f35
|| ' NULL, ' --c036 => f36
|| ' NULL, ' --c037 => f37
|| ' NULL, ' --c038 => f38
|| ' NULL, ' --c039 => f39
|| ' NULL, ' --c040 => f40
|| ' NULL, ' --c041 => f41
|| ' NULL, ' --c042 => f42
|| ' NULL, ' --c043 => f43
|| ' NULL, ' --c044 => f44
|| ' NULL, ' --c045 => f45
|| ' NULL, ' --c046 => f46
|| ' ''O'', ' --c047 (for record status)
|| ' wwv_flow_item.md5(col_1, col_2, col_3, col_4, col_5) ' --c048 (for optimistic locking)
--c049 for (not used in collection/reserevered for seq_id array)
--c050 (not used in collection/reservered for delete checkbox array)
|| 'FROM some_table '
|| 'WHERE some_col = :PXX_ITEM_NAME';
l_bind_names(1) := 'PXX_ITEM_NAME';
l_bind_values(1) := v('PXX_ITEM_NAME');
apex_collection.create_collection_from_query_b(
p_collection_name => l_collection_name,
p_query => l_query,
p_names => l_bind_names,
p_values => l_bind_values
);
IF :REQUEST = 'ADD'
THEN
apex_collection.add_member(
p_collection_name => l_collection_name
);
END IF;
END;
第二步成功创建集合后，您可以通过直接查询集合来对其进行报告，并使用APEX_ITEM包将您的字段设置为正确的项目，请注意第五项是链接到集合上第50个字段的复选框。再一次，它下面的代码只是一个例子：
SELECT apex_item.hidden(47,c047,NULL,'f47_'|| '#ROWNUM#')
|| apex_item.hidden(48,c048,NULL,'f48_'|| '#ROWNUM#')
|| apex_item.hidden(49,seq_id,NULL,'f49_'|| '#ROWNUM#')
|| apex_item.hidden(1,c001,NULL,'f01_'|| '#ROWNUM#')
|| apex_item.checkbox(
50,
seq_id,
NULL,
CASE
WHEN c047 = 'D' THEN seq_id
END,
':',
'f50_' || '#ROWNUM#'
) AS delete_checkbox,
apex_item.text(
2,
c002,
20,
50,
NULL,
'f02_' || '#ROWNUM#'
) AS col_2,
apex_item.text(
3,
c003,
20,
50,
NULL,
'f03_' || '#ROWNUM#'
) AS col_3,
apex_item.select_list_from_lov_xl(
4,
NVL(c004, '-1'),
'NAMED_LOV',
NULL,
'YES',
'-1',
'- Select Value -',
'f04_' || '#ROWNUM#'
) AS col_4,
apex_item.select_list_from_lov(
5,
NVL(c005, '-1'),
'NAMED_LOV',
NULL,
'YES',
'-1',
'- Select Value -',
'f05_' || '#ROWNUM#'
) AS col_5
FROM apex_collections
WHERE collection_name = 'REPLACE_NAME'
ORDER BY c003
第三步那么，现在您有一个集合显示可以在页面中修改的项目，但是否会立即将更改发布到集合中？ ...不，你需要先更新集合，因为你有这个代码，这里它处理更新，行创建和行删除。
DECLARE
l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
l_original_md5 VARCHAR2(32);
l_latest_md5 VARCHAR2(32);
BEGIN
l_collection_name := 'REPLACE_NAME';
FOR x IN 1 .. apex_application.g_f49.count
LOOP
IF apex_application.g_f01(x) IS NOT NULL --ID exists, check to see if record was updated
THEN
SELECT c048
INTO l_original_md5
FROM apex_collections
WHERE collection_name = l_collection_name
AND seq_id = apex_application.g_f49(x);
l_latest_md5 := wwv_flow_item.md5(
apex_application.g_f01(x),
apex_application.g_f02(x),
apex_application.g_f03(x),
apex_application.g_f04(x),
apex_application.g_f05(x)
);
IF l_original_md5 != l_latest_md5
THEN
apex_collection.update_member(
p_collection_name => l_collection_name,
p_seq => apex_application.g_f49(x),
p_c001 => apex_application.g_f01(x),
p_c002 => apex_application.g_f02(x),
p_c003 => apex_application.g_f03(x),
p_c004 => apex_application.g_f04(x),
p_c005 => apex_application.g_f05(x),
p_c047 => 'U',
p_c048 => apex_application.g_f48(x)
);
END IF;
ELSE --ID does not exist, must be new record
apex_collection.update_member(
p_collection_name => l_collection_name,
p_seq => apex_application.g_f49(x),
p_c001 => apex_application.g_f01(x),
p_c002 => apex_application.g_f02(x),
p_c003 => apex_application.g_f03(x),
p_c004 => apex_application.g_f04(x),
p_c005 => apex_application.g_f05(x),
p_c047 => 'N',
p_c048 => apex_application.g_f48(x)
);
END IF;
END LOOP;
IF :REQUEST = 'DELETE'
THEN
FOR x IN 1 .. apex_application.g_f50.count
LOOP
apex_collection.update_member_attribute(
p_collection_name => l_collection_name,
p_seq => apex_application.g_f50(x),
p_attr_number => '47',
p_attr_value => 'D'
);
END LOOP;
END IF;
END;
最后第四步这里我们根据对集合所做的更改来更新表。使用第47和第50个字段，我们知道应更新，删除或创建哪些字段：
DECLARE
l_table_md5 VARCHAR2(32);
l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
l_del_count PLS_INTEGER := 0;
l_upd_count PLS_INTEGER := 0;
l_ins_count PLS_INTEGER := 0;
l_success_message VARCHAR2(32767);
CURSOR op_lock_check_cur (
p_id IN NUMBER
)
IS
SELECT wwv_flow_item.md5(col_1, col_2, col_3, col_4, col_5)
FROM some_table
WHERE col_1 = op_lock_check_cur.p_id
FOR UPDATE;
BEGIN
l_collection_name := 'REPLACE_NAME';
FOR x IN (
SELECT *
FROM apex_collections
WHERE collection_name = l_collection_name
AND c047 IN ('N','U','D')
)
LOOP
IF x.c047 = 'N'
THEN
INSERT INTO some_table(
col_1,
col_2,
col_3,
col_4,
col_5
) VALUES (
some_table_seq.nextval,
x.c002,
x.c003,
x.c004,
x.c005
);
l_ins_count := l_ins_count + 1;
ELSIF x.c047 = 'U'
THEN
--Optimistic lock check
--MD5 should be identical to collection initialization proc
OPEN op_lock_check_cur(x.c001);
FETCH op_lock_check_cur INTO l_table_md5;
-- Compare the checksum values and if they are different, raise an error.
IF l_table_md5 != x.c048
THEN
raise_application_error(
-20001,
'Current version of data in database has changed '
|| 'since user initiated update process.'
);
END IF;
UPDATE some_table
SET col_2 = x.c002,
col_3 = x.c003,
col_4 = x.c004,
col_5 = x.c005
WHERE CURRENT OF op_lock_check_cur;
CLOSE op_lock_check_cur;
l_upd_count := l_upd_count + 1;
ELSIF x.c047 = 'D'
THEN
DELETE FROM some_table
WHERE col_1 = x.c001;
l_del_count := l_del_count + 1;
END IF;
END LOOP;
apex_collection.delete_collection(p_collection_name => l_collection_name);
l_success_message :=
l_ins_count || ' rows inserted, ' ||
l_upd_count || ' rows updated, ' ||
l_del_count || ' rows deleted';
:PX_SUCCESS_MESSAGE := l_success_message;
END;
这就是全部，但是从头到脚再次查看教程，有很多我不能在这里发布的信息。
免责声明：我不是技能大师代表，我对视频没有任何权利，我也不会以任何方式推广技能构建者网页。我只是一个程序员，发现本教程很有用。