如果我通过ssh执行命令，则输出不正确

Question

以下命令的输出

sudo find / -xdev -type f -size +100000 -name "*.log" -exec gzip -v {} \; 2>&1 | awk '{print $6}'

给我

/opt/testing3/cat1.log.gz
/opt/testing3/cat2.log.gz
/opt/testing3/cat3.log.gz
/opt/testing3/cat4.log.gz
/opt/testing3/cat5.log.gz
/opt/testing3/cat6.log.gz
/opt/testing3/cat7.log.gz

但是，如果我通过ssh这样做，它会给我：

 ssh user@hostname "sudo find / -xdev -type f -size +100000 -name \"*.log\" -exec gzip -v {} \; 2>&1 | awk '{print $6}'"

结果

/opt/testing3/cat1.log:  95.4% -- replaced with /opt/testing3/cat1.log.gz
/opt/testing3/cat2.log:  95.4% -- replaced with /opt/testing3/cat2.log.gz
/opt/testing3/cat3.log:  95.4% -- replaced with /opt/testing3/cat3.log.gz
/opt/testing3/cat4.log:  95.4% -- replaced with /opt/testing3/cat4.log.gz
/opt/testing3/cat5.log:  95.4% -- replaced with /opt/testing3/cat5.log.gz
/opt/testing3/cat6.log:  95.4% -- replaced with /opt/testing3/cat6.log.gz
/opt/testing3/cat7.log:  95.4% -- replaced with /opt/testing3/cat7.log.gz

为什么输出不同？似乎awk没有被执行。

Answer 1

你必须逃避＆＃34; $＆＃34;符号，为了不在本地获取，而是远程传递。

$ ssh $HOSTNAME "ls -l /tmp | tail -1 | awk '{print $6}'"
-rw-r--r-- 1 root     root       0 Apr 29 01:31 file.log
$ ssh $HOSTNAME "ls -l /tmp | tail -1 | awk '{print \$6}'"
Apr