每当我执行程序时,平均更改总是为0,我不明白为什么。
/*LuckySevens.java
Simulate the game of lucky sevens until all funds are depleted.
1) Rules:
roll two dice
if the sum equals 7, win $4, else lose $1
2) The inputs are:
the amount of money the user is prepared to lose
3) Computations:
use the random number generator to simulate rolling the dice
loop until the funds are depleted
count the number of rolls
keep track of the maximum amount
4) The outputs are:
the number of rolls it takes to deplete the funds
the maximum amount
the average net change after 100 rolls
*/
import java.util.Scanner;
import java.util.Random;
public class LuckySevens {
public static void main (String [] args) {
Scanner reader = new Scanner(System.in);
Random generator = new Random();
int die1, die2, // two dice
dollars, // initial number of dollars (input)
countAtMax, // count when the maximum is achieved
count, // number of rolls to reach depletion
maxDollars, // maximum amount held by the gambler
averageWin, // the average net change after 100 rolls
initialDollars; // initial amount of money user has
// Request the input
System.out.print("How many dollars do you have? ");
dollars = reader.nextInt();
// Initialize variables
maxDollars = dollars;
initialDollars = dollars;
countAtMax = 0;
count = 0;
// Loop until the money is gone
while (dollars > 0){
count++;
// Roll the dice.
die1 = generator.nextInt (6) + 1; // 1-6
die2 = generator.nextInt (6) + 1; // 1-6
// Calculate the winnings or losses
if (die1 + die2 == 7)
dollars += 4;
else
dollars -= 1;
// If this is a new maximum, remember it
if (dollars > maxDollars){
maxDollars = dollars;
countAtMax = count;
}
/* TODO:FIX BELOW STATEMENT
it always returns influx as 0 */
if (count == 100) {
averageWin = ((maxDollars - initialDollars) / 100);
System.out.println ("In the first 100 rolls there an average money influx of " + averageWin + " per roll.") ;
}
}
// Display the results
System.out.println
("You went broke after " + count + " rolls.\n" +
"You should have quit after " + countAtMax +
" rolls when you had $" + maxDollars + ".");
}
}
答案 0 :(得分:3)
将 averageWin 设为 double 变量。
将平均胜利的计算更改为
averageWin =((double)maxDollars - (double)initialDollars)/ 100;