我创建了一个类如下
public class Table
{
public enum ColumnNames
{
ID,
TableName,
Active,
Date
}
public List<TableParameter> Parameters { get; set; }
}
public enum Types
{
INT,
STRING,
DATETIME,
BOOLEAN,
DECIMAL
}
public class TableParameter
{
public Table.ColumnNames ParameterName { get; set; }
public Types? Tip { get; set; }
public dynamic Value { get; set; }
}
当我尝试像下面这样使用它时,我得到一个空对象引用错误。
Table tb3 = new Table();
tb3.Parameters.Add(new TableParameter() { ParameterName = Table.ColumnNames.ID, Value = 1, Tip = Types.INT });
希望你能帮助我。我会等你的回答。
答案 0 :(得分:4)
您需要初始化tb3.Parameters
Table tb3 = new Table();
tb3.Parameters = new List<TableParameter>();
tb3.Parameters.Add(new TableParameter() { ParameterName = Table.ColumnNames.ID, Value = 1, Tip = Types.INT });
或者您可以在Table
类构造函数本身中初始化,如下所示
public class Table
{
public Table()
{
Parameters = new List<TableParameter>();
}
}
答案 1 :(得分:2)
您永远不会初始化Parameters
。尝试在类Table
的构造函数中初始化public class Table
{
public Table()
{
Parameters = new List<TableParameter>();
}
public enum ColumnNames
{
ID,
TabloName,
Active,
Date
}
public List<TableParameter> Parameters { get; set; }
}
属性。
<?php
$lastDate = '';
while($row = > $played){
$gameDate = $row['event_date'];
$team1 = $row['team1'];
$team2 = $row['team2'];
$venue = $row['venue'];
$eventId = $row['event_id'];
if($gameDate !== $lastDate) {
echo'<tr>';
$lastDate = $gamedate;
echo $echoed ='<td>Today,'.$gameDate.'echo</td>';
echo'</tr>';
}
echo'<tr>';
echo'<td>'.$team1.'</td>';
echo'<td>'.$team2.'</td>';
echo'<td>'.$venue.'</td>';
答案 2 :(得分:0)
谢谢。我更新了我的代码,如下所示;
public class Table
{
public enum ColumnNames
{
ID,
TableName,
Active,
Date
}
public List<TableParameter> Parameters;
public Table()
{
Parameters = new List<TableParameter>();
}
}