Question

 UserAccountServiceImpl service = applicationContext.getBean("UserAccountServiceImpl", UserAccountServiceImpl.class);
 service =SpringContextListener.getBean("UserAccountServiceImpl", UserAccountServiceImpl.class);

我的代码就像上面一样。我以两种方式调用getBean。第一种方式运行perfact，但第二种方式抛出异常，如此

org.springframework.beans.factory.NoSuchBeanDefinitionException：没有名为＆＃39; UserAccountServiceImpl＆＃39;已定义

applictionContext来自implements ApplicationContextAware SpringContextListener如下所示：

 <bean id="springContextListener" class="com.xxxx.xxx.SpringContextListener"/>

public final class SpringContextListener implements BeanFactoryAware {

    private static BeanFactory beanFactory;

    public static BeanFactory getBeanFactory() {
        return beanFactory;
    }

    public void setBeanFactory(BeanFactory beanFactory) {
        if(SpringContextListener.beanFactory != null) {
            throw new RuntimeException("beanFactory inited .............");
        }
        SpringContextListener.beanFactory = beanFactory;
    }

    public static <T> T getBean(String beanName, Class<T> clazs) {  
        return clazs.cast(beanFactory.getBean(beanName));  
    }  
}

applicationContext和beanfactory有什么区别？我的代码问题是什么？

Answer 1

我在application-context.xml

中添加了UserAccountServiceImpl作为bean

ApplicationContext applicationContext =
    newClassPathXmlApplicationContext("application-context.xml");

UserAccountServiceImpl service = applicationContext.getBean("UserAccountServiceImpl",
    UserAccountServiceImpl.class);

System.out.println(service);

service=SpringContextListener.getBean("UserAccountServiceImpl",UserAccountServImpl.class);

System.out.println(service);

结果：

UserAccountServiceImpl [toString()=com.vl.test.UserAccountServiceImpl@3834d63f]
UserAccountServiceImpl [toString()=com.vl.test.UserAccountServiceImpl@3834d63f]

ApplicationContext beanfactory org.springframework.beans.factory.NoSuchBeanDefinitionException：

1 个答案: