Question

我在解析来自Web服务响应的数据时遇到问题。我调用了一个Web服务并将响应作为NSLog，但我需要将数据捕获为NSString。

以下是我的示例代码：

-(void)connection:(NSURLConnection *) connection didReceiveResponse:   (NSURLResponse *) response {

}

-(void)connection:(NSURLConnection *) connection didReceiveData:(NSData *) data {
    NSString *strData;
    strData = [[NSString alloc]initWithData:data encoding:NSUTF8StringEncoding];

    NSXMLParser   *xmlParser = [[NSXMLParser alloc] initWithData:data];
    [xmlParser setDelegate:self];
    [xmlParser parse];

    soapResultsString=[[NSMutableString alloc]init];

    recordResults =YES;
}

 NSString *xmlparserString;
 NSMutableString *soapResultsString;
 bool recordResults;

-(void)parserDidEndDocument:(NSXMLParser *)parser
{
}

-(void)parser:(NSXMLParser *)parser didStartElement:(NSString     *)elementName namespaceURI:(NSString *) namespaceURI qualifiedName:(NSString *)qName attributes: (NSDictionary *)attributeDict
{
    xmlparserString=elementName;

    if( [xmlparserString isEqualToString:@"ns:return"])
    {
        recordResults =YES;
        soapResultsString = [[NSMutableString alloc] init];
    }
}

-(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string { 
    if( recordResults )
    {
        [soapResultsString appendString: string];
        NSLog(@"inside%@",string);
    }

}

-(void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName {
    if( [elementName isEqualToString:@"ns:return"])
    {
        NSLog(@"parser==>%@",parser);
        NSLog(@"nameSpaceUrL==>%@",namespaceURI);
        NSLog(@"qName==>%@",qName);

        NSData *data = [soapResultsString dataUsingEncoding:NSUTF8StringEncoding];
        NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
    //   NSLog(@"json==>%@",json);

        NSArray *planArray = [json objectForKey:@"hello_History"];

        NSLog(@"planArrayCount==>%lu",(unsigned long)[planArray count]);
        NSMutableArray *dataSource = [NSMutableArray arrayWithCapacity:planArray.count];
        for (int i = 0 ; i<[planArray count]; i++)
        { 
            recordResults = NO;

            txn_id=[[[json valueForKey:@"hello_History"]valueForKey:@"date"]objectAtIndex:i];

            loginId = [[[json valueForKey:@"hello_History"]valueForKey:@"time"]objectAtIndex:i];

        }
    }
}

问题是我得到输出到这个方法

-(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string

但我的解析方法不在调用

-(void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName

是否有其他方法可以捕获字符串

如何将Web服务数据解析为NSString？

0 个答案: