Question

我有以下表格：

location_location
----------------
id       
name     
email             

sales_sale
---------
id
date
total_amount
location_id
client_id

client_client
-------------
id 
name

我想创建一个查询，该查询提供Sales列的SUM，并按月，位置和客户名称对结果进行分组，如下所示：

Desired Result:
Location name  /  month /  sum(total_amount) / client_name
San Francisco      Jan        250                CISCO

我的尝试：

select name(select name from location_location),
to_char(date,'Mon') as mon,
sum("total_amount") as "total_amount",
client_amount    
from sales_sale
group by 1,3
order by mon desc

INNER JOIN name ON client_client.id =sales_sale.client_id and 
INNER JOIN location ON location_location.id =sales_sale.location_id;

Answer 1

虽然你的语法略有偏差，但你还是有了正确的想法：

SELECT   l.name, 
         TO_CHAR(date, 'MON')
         client_name,
         SUM(total_amount)
FROM     location_location l
JOIN     sales_sale s ON s.location_id = l.id
JOIN     client_client c ON s.client_id = c.id
GROUP BY l.name, 
         TO_CHAR(date, 'MON')
         client_name

按位置，客户名称和月份对查询结果进行分组

1 个答案: