Question

我有一个分为多行的表。该表如下所示：

表admissions：

PersonID    Field_Value 
------------------------
  1775      UNDECIDED
  1775      PC-STJ
  1775      N/A
  1775      DEMENTIA
  1775      STJ
  1775      0
  1775      N/A
  1775      N/A
  1775      N

我有一个视图将捕获如下所示的一行信息。

请注意，以上是它在数据库中为我提供的与UI不同的内容。

1775,  UNDECIDED, PC -STJ, N/A, DEMENTIA, STJ, 0, N/A, N/A, N

Answer 1

试试这个：

    SELECT o.PersonID , fieldvalues = STUFF(
    (SELECT ',' + field_value 
          FROM admissions i
          where i.PersonID= o.PersonID
          FOR XML PATH (''))
         , 1, 1, '')
    from admissions o. Group by  o.PersonID ;

Answer 2

DECLARE @Admission TABLE (PersonID INT, Field_Value VARCHAR(25));
INSERT INTO @Admission
    VALUES  (1775,'UNDECIDED'),
            (1775,'PC-STJ'),
            (1775,'N/A'),
            (1775,'DEMENTIA'),
            (1775,'STJ'),
            (1775,'0'),
            (1775,'N/A'),
            (1775,'N/A'),
            (1775,'N');

SELECT  PersonID,
        STUFF(
                (
                    SELECT ', ' + Field_Value
                    FROM @Admission
                    WHERE PersonID = A.PersonID
                    FOR XML PATH('')
                ),
        1,2,'') AS Field_Values
FROM @Admission A
GROUP BY PersonID

结果：

PersonID    Field_Values
----------- ------------------------------------------------------
1775        UNDECIDED, PC-STJ, N/A, DEMENTIA, STJ, 0, N/A, N/A, N

T-SQL / SQL Server逻辑选择

2 个答案: