嘿所有我需要以下html代码才能获得“提供最佳微笑”的价值,这似乎是 6 prev()和 2 Next ()
gyp ERR! configure error
gyp ERR! stack Error: spawn C:\tools\pyhton2 ENOENT
gyp ERR! stack at exports._errnoException (util.js:746:11)
gyp ERR! stack at Process.ChildProcess._handle.onexit (child_process.js:1046:32)
gyp ERR! stack at child_process.js:1137:20
gyp ERR! stack at process._tickCallback (node.js:355:11)
gyp ERR! System Windows_NT 6.3.9600
gyp ERR! command "node" "C:\\Program Files\\nodejs\\node_modules\\npm\\node_modules\\node-gyp\\bin\\node-gyp.js" "rebuild"
gyp ERR! cwd C:\test\node_modules\xsl-transform\node_modules\node_xslt
gyp ERR! node -v v0.12.1
gyp ERR! node-gyp -v v1.0.2
gyp ERR! not ok
npm ERR! Windows_NT 6.3.9600
npm ERR! argv "C:\\Program Files\\nodejs\\\\node.exe" "C:\\Program Files\\nodejs\\node_modules\\npm\\bin\\npm-cli.js" "install" "xsl-transform"
npm ERR! node v0.12.1
npm ERR! npm v2.5.1
npm ERR! code ELIFECYCLE
npm ERR! node_xslt@0.1.9 preinstall: `node-gyp rebuild`
npm ERR! Exit status 1
npm ERR!
npm ERR! Failed at the node_xslt@0.1.9 preinstall script 'node-gyp rebuild'.
npm ERR! This is most likely a problem with the node_xslt package,
npm ERR! not with npm itself.
npm ERR! Tell the author that this fails on your system:
npm ERR! node-gyp rebuild
npm ERR! You can get their info via:
npm ERR! npm owner ls node_xslt
npm ERR! There is likely additional logging output above.
npm ERR! Please include the following file with any support request:
npm ERR! C:\test\npm-debug.log
我当时的位置是输入标记的达到并保持质量值。
目前我尝试了以下内容:
<div id="eea305a4-32b2-434d-8623-4dc3e2fcf119F_SelectMany" class="lfFormField
lfFormFieldSelectMany F_Form1-P_NewPage-F_SelectMany">
<div class="">
<fieldset class="composite-field-fieldset">
<legend class="no-form-field-mandatory-sign-css">
<span id="F_SelectMany-required"
class="form-field-mandatory-sign-css lfFormFieldRequiredMarker no-form-field-mandatory-sign-css">*</span>
<span class="form-field-title-sign-css lfFormLabel">deliver best smile</span>
</legend>
<div style="padding=left:0.1em"
dojoattachevent="onmouseover:onMouseOver, onclick:onClick, onmouseout:onMouseOut"
class="dojoDndHandle freedom-base-mixin-css"
id="eea305a4-32b2-434d-8623-4dc3e2fcf119F_SelectMany-widget"
widgetid="eea305a4-32b2-434d-8623-4dc3e2fcf119F_SelectMany-widget">
<ul id="e2b7488e-a88c-4da0-8287-4f8e4e6091f4tbl"
dojoattachpoint="containerNode,focusNode"
class="selection-group">
<li dojoattachpoint="listItem"
class="vertical-selection-group-item"
id="freedom_widget_solution_form_FreedomOptionButton_0"
value="0" type="checkbox"
widgetid="freedom_widget_solution_form_FreedomOptionButton_0">
<div class="selection-group-item-container notDojoDndHandle">
<span dojoattachevent="onmouseover:onMouseOver, onclick:onClick, onmouseout:onMouseOut"
class="selection-group-item-input dijitInline freedom-base-mixin-css freedom-base-mixin-cssChecked dijitChecked"
widgetid="2ff949f4-c88e-4769-8e36-23c81661af92-btn">
<input dojoattachpoint="textbox,focusNode,_aroundNode"
id="2ff949f4-c88e-4769-8e36-23c81661af92-btn"
class="dijitReset dijitCheckBox notDojoDndHandle"
type="checkbox" tabindex="0"
dojoattachevent="onclick:_onClick"
role="checkbox" aria-checked="true"
name="group_eea305a4-32b2-434d-8623-4dc3e2fcf119F_SelectMany-widget"
value="Achieve and maintain quality"
style="-webkit-user-select: none;">
</span>
<div class="selection-group-item-text-container dijitInline">
<label dojoattachpoint="titleNode"
for="2ff949f4-c88e-4769-8e36-23c81661af92-btn"
class="selection-group-item-text bold-selection-group-item">Achieve and maintain quality</label>
</div>
</div>
</li>
var testing 是我试图从中获取该值但却出现“未定义”所以我猜我没有停在正确的位置?
任何帮助都会很棒!
答案 0 :(得分:5)
您可以尝试遍历父容器,然后通过它的类对该元素进行查找。
例如:
通过id遍历父级:
$(this).closest('#eea305a4-32b2-434d-8623-4dc3e2fcf119F_SelectMany').find('.form-field-title-sign-css');
按类遍历父级:
$(this).closest('.lfFormField').find('.form-field-title-sign-css');
或通过HTML元素遍历父级:
$(this).closest('fieldset').find('.form-field-title-sign-css');
要获得该值,在这种情况下,您可能希望.text()
而不是.html()
。当然,除非你真的想要所有的HTML。
最后,如果此ID F_SelectMany-required
不是随机的。你可以这样做。这应该有助于它更具体一点。
$(this).closest('.lfFormField').find('#F_SelectMany-required').children('.form-field-title-sign-css');
答案 1 :(得分:0)
检查此代码
$(function(){
var $lbl=$("label[dojoattachpoint='titleNode']"); //Your position
$lbl.click(function(){
if (!$("#" + $(this).attr("for")).is(":checked")) {
var $fieldset=$(this).closest("fieldset");
alert($("legend",$fieldset).find("span").text());
}
})
})
答案 2 :(得分:0)
Jquery的prev()为您提供之前的兄弟。在您发布的文档的DOM中,值中的“达到并保持质量”的输入没有任何兄弟姐妹。它是围绕它的跨度的唯一孩子,所以无论你使用prev()和next()的组合,你都将得到未定义。你的意思是使用parent()而不是prev()吗? 但更好的是给那个跨度一个id 带来最好的笑容 并使用$(“#SmileSpanId”)
来实现它