我提取各个日期的总帐户余额,需要计算这些帐户总余额之间的差异,但需要解决方案。
SQL:
SELECT SNAPSHOT_DATE,
SUM(ACCOUNT_BALANCE_AMOUNT) SAVINGS_BALANCES
FROM pIDWUserVW.PRODUCT_SAVINGS_VW
WHERE SNAPSHOT_DATE IN ('2015-01-02', '2015-01-30', '2015-02-02', '2015-02-27', '2015-03-31')
GROUP BY SNAPSHOT_DATE
ORDER BY SNAPSHOT_DATE ASC;
结果:
SNAPSHOT_DATE SAVINGS_BALANCES
1/2/2015 10,407,069,092.55
1/30/2015 10,581,034,604.38
2/2/2015 10,525,024,786.77
2/27/2015 11,105,597,533.96
3/31/2015 11,371,511,747.20
这是我想要的(“差异”栏目),但我找不到合适的功能来执行此操作:
SNAPSHOT_DATE SAVINGS_BALANCES DIFFERENCE
1/2/2015 10,407,069,092.55
1/30/2015 10,581,034,604.38 173,965,511.83
2/2/2015 10,525,024,786.77 (56,009,817.61)
2/27/2015 11,105,597,533.96 580,572,747.19
3/31/2015 11,371,511,747.20 265,914,213.24
我正在使用Teradata SQL Assistant并且当我尝试像MDIFF这样的函数但是我可能做错了时,会出现仅允许使用窗口函数的错误。
答案 0 :(得分:1)
窗口聚合函数是在聚合后计算的,您需要一个LEAD函数,该函数未在Teradata中实现,但可以轻松模拟:
SELECT SNAPSHOT_DATE,
SUM(ACCOUNT_BALANCE_AMOUNT) SAVINGS_BALANCES,
SUM(ACCOUNT_BALANCE_AMOUNT) -- current value
- MIN(SUM(ACCOUNT_BALANCE_AMOUNT)) -- previous row's value
OVER (ORDER BY SNAPSHOT_DATE
ROWS BETWEEN 1 PRECEDING AND 1 PRECEDING) AS DIFFERENCE
FROM pIDWUserVW.PRODUCT_SAVINGS_VW
WHERE SNAPSHOT_DATE IN ('2015-01-02', '2015-01-30', '2015-02-02', '2015-02-27', '2015-03-31')
GROUP BY SNAPSHOT_DATE
ORDER BY SNAPSHOT_DATE ASC;