Question

我的ExpandableListView一直是特定群体的单身儿童。对于某些群组，我希望隐藏子项，但我希望群组仍然可以点击（点击后每个群组项目都会更改它的布局）。那么应该从getChildView？

为这些群体返回什么

Answer 1

覆盖getChildrenCount并为您想要的群组返回0，就好像他们没有孩子一样。它们仍然可以点击。

@Override
public int getChildrenCount(int groupPosition) {
    if (groupPosition == 1) {
        return 0;
    } else {
        return super.getChildrenCount(groupPosition);
    }
}

Answer 2

以下是我认为，代码未经过测试

public view getChildView(int groupPosition, int ChildPosition, boolean b, View view, ViewGroup viewGroup){
if(!groupPostion)//for the group you dont want the layout to be displayed
v=your custom view for the child items.//or if you know the exact position define it like 
//if or use switch (groupPosition==something){v.setVisibility(View.GONE)}
return v;
}

Answer 3

您需要致电collapseGroup()。同样在您的构造函数中，您需要ExpandableListView

public class YourExapandableAdapter extends BaseExpandableListAdapter {

    private Context mContext;
    ExpandableListView mExpandableListView;
    int mLastExpandedGroupPosition = -1;

    public YourExapandableAdapter(Context context, ExpandableListView expandableListView) {
            mContext = context;
            mExpandableListView = expandableListView;
    }

    @Override
    public void onGroupExpanded(int groupPosition) {
        super.onGroupExpanded(groupPosition);
        if(groupPosition != mLastExpandedGroupPosition){
                mExpandableListView.collapseGroup(mLastExpandedGroupPosition);
        }

        mLastExpandedGroupPosition = groupPosition;
    }

在这种情况下，我隐藏了最后一组，但您可以使用当前组或任何您想要的组。

如何在ExpandableListView中隐藏特定组的子项？

3 个答案: