我需要一个查询,它会给出与某些值相对应的行,无论其值是否为null,或者表中是否存在这些值。
E.g。
SELECT spot_key, market,panel_member, SUM(weight) as TVR
FROM break_minute_tvr_fixed b
WHERE b.column1 in (1,3,4,2,3,4)
and b.section in (1,2,3,4)
and b.sex in (1,2)
and b.age in (1,2,3,4,5,6,7)
and b.market in ('9')
and spot_key in ( '1:20141017:2129' )
GROUP BY spot_key, market;
这会将行返回为:
+-----------------+--------+---------------------+--------------------+
| spot_key | market | panel_member | TVR |
+-----------------+--------+---------------------+--------------------+
| 1:20141017:2129 | 9 | 010583010102;7.2930 | 134.65280079841614 |
+-----------------+--------+---------------------+--------------------+
1 row in set (0.00 sec)
现在,如果我将另一个值添加到市场列表中,比如表300本身不存在,那么我的查询将成为:
SELECT spot_key, market,panel_member, SUM(weight) as TVR
FROM break_minute_tvr_fixed b
WHERE b.column1 in (1,3,4,2,3,4)
and b.section in (1,2,3,4)
and b.sex in (1,2)
and b.age in (1,2,3,4,5,6,7)
and b.market in ('9','300')
and spot_key in ( '1:20141017:2129' )
GROUP BY spot_key, market;
它给我与上面相同的输出。但我需要以下内容:
+-----------------+--------+---------------------+--------------------+
| spot_key | market | panel_member | TVR |
+-----------------+--------+---------------------+--------------------+
| 1:20141017:2129 | 300 | | 0 |
| 1:20141017:2129 | 9 | 010583010102;7.2930 | 134.65280079841614 |
+-----------------+--------+---------------------+--------------------+
答案 0 :(得分:2)
您可以使用left join
:
SELECT spot_key, m.market, panel_member, SUM(weight) as TVR
FROM (SELECT '9' as market UNION ALL SELECT '300'
) LEFT JOIN
break_minute_tvr_fixed b
ON b.market = m.market and
b.column1 in (1,3,4,2,3,4) and
b.section in (1,2,3,4) and
b.sex in (1,2) and
b.age in (1,2,3,4,5,6,7) and
b.spot_key in ( '1:20141017:2129' )
GROUP BY spot_key, market;
当然spot_key
将为NULL
,除非您明确为其指定值:
SELECT '1:20141017:2129' as spot_key, m.market, panel_member, SUM(weight) as TVR