当我试图打印我的2D矢量时,它只读取第3行(这是迷宫的第一行)并忽略其余的迷宫。我的迷宫是这样的;
11
11
X XXXXXXXXX
X X 1 X
X XXXXX X X
X X X 1
XXXXX XXX X
X X X X
X X XXX X X
X X X X
X XXXXXXX X
X X
XXXXXXXXXXX
但我的最终结果就是像那样重写第一行;
11
11
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
X XXXXXXXXX
显然我在我的while循环中误会了一些事情......
#include <iostream>
#include <stdio.h>
#include "Maze.h"
#include "hw2.cpp"
void PrintVec2D(vector< vector< char> > &v)
{
for (size_t i=0; i<v.size(); i++)
{
for(size_t j=0; j<v[i].size(); j++)
cout << v[i][j];
cout << '\n';
}
}
void PrintVec1D(vector<char> &v)
{
for (size_t i=0; i<v.size(); i++)
cout<< v[i];
}
int main(int argc, char *argv[]){
string line;
ifstream myfile (argv[1]);
if (myfile.is_open())
{
//read just first two lines for rows and cols
string firstline;
getline(myfile, firstline);
int rows = std::stoi(firstline);
string secondline;
getline(myfile, secondline);
int cols=std::stoi(secondline);
//create 2d vector
vector< vector<char> > _maze;
//read rest of the file for maze structure
//I think my problem is in this while loop...
string line2;
int ra = 0;
int rb = 0;
while(ra<cols)
{
getline(myfile, line2);
vector<char> newRow(line2.begin(),line2.end());
while (rb<rows)
{
_maze.push_back(newRow);
ra++;
rb++;
}
}
PrintVec2D(_maze);
myfile.close();
}
else cerr << "Unable to open file";
return 0;
}
答案 0 :(得分:1)
你的循环应如下所示:
for(size_t ra = 0; ra < cols; ++ra)
{
std::string line;
if(std::getline(myfile, line))
{
vector<char> newRow(line.begin(), line.end());
_maze.push_back(newRow);
// or just _maze.emplace_back(line.begin(), line.end());
}
}
我无法找到第二个循环和rb
变量的用法。由于newRow
已经是一个数组,为每一行添加它的重点是什么?