Question

我在表'事件'中使用了一个列'标题'。此列包含一些信息。在此信息中，三个字符表示区域。这三个字符通常在（'on'，'：'）之后找到。我想执行一个函数（mysql），该函数允许：1）如果从'Title'列中取出的三个字符（位于'on'之后）是（kef或bej或jen），那么结果将存储在列'test'在同一个表中。 2）如果第一个没有实现，则取出位于'：'之后的三个字符，并存储在同一个表中的'test1'列中。有我使用的代码：

WITH CTE AS (
SELECT c.ChallanNo, c.REFERENCENO , c.STEPNO FROM CHALLAN c
INNER JOIN CURRENTREPORT cr
on c.REFERENCENO = cr.REFERENCENO
WHERE RECEIVEDDATE IN (SELECT MIN(RECEIVEDDATE)
FROM CHALLAN cn
GROUP BY (STEPNO))
)

UPDATE CURRENTREPORT SET WORK1 = ch.STEPNO FROM CURRENTREPORT c INNER JOIN cte ch 
on c.referenceNo = ch.referenceNo

并且我使用了查询：

delimiter |
CREATE FUNCTION METTER5 (s VARCHAR(2000)) RETURNS VARCHAR(10000)
DETERMINISTIC
   BEGIN
         DECLARE open  INT;
           DECLARE close  INT;
           DECLARE someLimit  INT;
           DECLARE str  VARCHAR(2000);
           DECLARE str1  VARCHAR(2000);
            DECLARE str2  VARCHAR(2000);
            DECLARE str3  VARCHAR(2000);
           DECLARE toFind  VARCHAR(2000);
           DECLARE co VARCHAR(2000);
           SET co='';
           SET open = 1;
           SET close = 1;
           SET toFind = s ;
           SET someLimit =100;
           SET str='';
           SET str1='';
           SET str2='';
         /* SET tofind=concat(tofind,'sur','');*/
 SET str =substring(trim(substring_index(s,'sur',-1)),1,3);           
 SET str1 =substring(trim(substring_index(s,'du',-1)),1,3);
 SET str2 =substring(trim(substring_index(s,':',-1)),1,3);

IF  (str in ('ZAG','TUN','TOZ','TAT','SOS','SIL','SFX','SBO','RNC','BAR','BEJ','BIZ','BSC','GAB','GAF','JEN','KAI','KAS','KEB','KEF','MAH','MED','MON','NAB')) =1 THEN set co = str ;
ELSE IF ((str not in ('ZAG','TUN','TOZ','TAT','SOS','SIL','SFX','SBO','RNC','BAR','BEJ','BIZ','BSC','GAB','GAF','JEN','KAI','KAS','KEB','KEF','MAH','MED','MON','NAB')) and (str1 in ('ZAG','TUN','TOZ','TAT','SOS','SIL','SFX','SBO','RNC','BAR','BEJ','BIZ','BSC','GAB','GAF','JEN','KAI','KAS','KEB','KEF','MAH','MED','MON','NAB')))=1 THEN set co = str1 ;
ELSE IF ((str1 not in ('ZAG','TUN','TOZ','TAT','SOS','SIL','SFX','SBO','RNC','BAR','BEJ','BIZ','BSC','GAB','GAF','JEN','KAI','KAS','KEB','KEF','MAH','MED','MON','NAB'))and (str2 in ('ZAG','TUN','TOZ','TAT','SOS','SIL','SFX','SBO','RNC','BAR','BEJ','BIZ','BSC','GAB','GAF','JEN','KAI','KAS','KEB','KEF','MAH','MED','MON','NAB')))=1 THEN SET co = str2 ;
ELSE set co = '1' ; 
END IF;
END IF;
END IF;
           return co;
   END |
 delimiter;

但是在运行之后，出现了问题：“字段列表”中的未知列'描述'

感谢。

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