Question

我有一个链接到预订表的用户表，因此我可以告诉用户做了哪些预订。我试图将用户表加入预订表，但它没有用。我还试图尝试传递会话userID，但它再次没有工作。我的PHP代码如下所示，我试图在一分钟内完成。

＆＃13;

	<?php
		include "config.php"; 
		
		//Booking point
		if(isset($_POST['booking']))
		{
			//get values for variables
			$pitchID = $_POST['pitchID'];
			$start_date = $_POST['start_date'];
			$start_hour = $_POST['start_hour'];
			$end_hour = $_POST['end_hour'];
			$booking_age = $_POST['booking_age'];
			$pitch_size = $_POST['pitch_size'];
			$light_tokens = $_POST['light_tokens'];
			
			$q = $db->prepare("SELECT * 
							  FROM booking  
							  LEFT JOIN user 
							  ON booking.userID=user.userID");
			$query = $q-> execute();
			
				if($query)
				{
					$q = $db->prepare("INSERT INTO booking SET pitchID = ?, start_date = ?, start_hour = ?, end_hour = ?, booking_age = ?, pitch_size = ?, light_tokens = ?");
					$query = $q->execute(array($pitchID,$start_date,$start_hour,$end_hour,$booking_age,$pitch_size,$light_tokens));
					$count = $q->rowCount();
					
					if($count == 1){
						echo "Your booking has been made";
						header("Location:home2_template.html");
						return; 
					}else {
						echo "Fail";
					}
				} else {
					echo"Booking already exists";
				}
		}
	?>

＆＃13;

Answer 1

我在系统的登录部分添加了会话变量，然后从那里传递了它。

以下登录部分：

＆＃13;

<?php
	include "config.php"; 
	if(isset($_POST['submit'])){

	$username = $_POST['username']; 
	$password = $_POST['password'];
	
	$q = $db->prepare("SELECT * FROM user WHERE username = ? AND password = ?");
	$query = $q->execute(array($username, $password));
	while($dbRow = $q->fetch(PDO::FETCH_ASSOC)) {
		$userID = $dbRow['userID'];
	}
	$count = $q->rowCount();
	if($count == 1){
		session_start(); 
		$_SESSION['userID'] = $userID; 
		header("Location:home2_template.html"); 
		return;
	}else{
		echo "You have entered an incorrect login/password";
		}
	}
?>

＆＃13;

我还删除了PHP代码中的连接，最后得到了以下内容。它通过我的userID传递，但是此代码中仍然存在任何正在查看此错误的人的错误。我必须在我的页面顶部声明变量userID，然后再在我的prepare语句中声明。

＆＃13;

<?php 
session_start(); 
 $userID = $_SESSION['userID']; 
?>

＆＃13;

<?php
		include "config.php"; 
		echo $userID; 
		//Booking point
		if(isset($_POST['booking']))
		{
			//get values for variables
			$pitchID = $_POST['pitchID'];
			$start_date = $_POST['start_date'];
			$start_hour = $_POST['start_hour'];
			$end_hour = $_POST['end_hour'];
			$booking_age = $_POST['booking_age'];
			$pitch_size = $_POST['pitch_size'];
			$light_tokens = $_POST['light_tokens'];
			
			$q = $db->prepare("INSERT INTO booking SET pitchID = ?, start_date = ?, start_hour = ?, end_hour = ?, booking_age = ?, pitch_size = ?, light_tokens = ?, userID='$userID'");
			$query = $q->execute(array($pitchID,$start_date,$start_hour,$end_hour,$booking_age,$pitch_size,$light_tokens));
			
			$count = $q->rowCount();
				if($count == 0)
				{
					echo "Your booking has been made";
					header("Location:home2_template.html");
					return; 
				}else {
					echo "That booking already exists";
				}
		}
	
	?>

＆＃13;

将userID传递到预订表

1 个答案: