我遇到的错误是" Stream不支持阅读"。我正在向网址发送一个Http帖子请求。以下是我正在使用的代码
var request = (HttpWebRequest) WebRequest.Create("https://test.com/Hotel Hospitality Source?method=fetchInfo");
var postData = "&username=testing";
postData += "&password=Testing";
postData += "&hotelId=h075-103";
var data = Encoding.ASCII.GetBytes(postData);
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = data.Length;
using(var ms = new MemoryStream())
request.GetRequestStream().CopyTo(ms);
var response = (HttpWebResponse) request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
首先,我使用了以下代码。
using (var stream = request.GetRequestStream())
{
stream.Write(data, 0, data.Length);
}
var response = (HttpWebResponse)request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
我在使用CopyTo方法进行流时遇到错误。如何解决此错误?
答案 0 :(得分:4)
UPDATE tbl_test
SET tag = case
when DBInstance = 'INS1' and DBName = 'master'
then 'a'
when DBInstance = 'INS2' and DBName = 'tempdb'
then 'b'
else NULL -- or may be tag, or default value which you want.
end
应该做什么?您正在尝试将请求流(只能写入)复制到您随后处理的新内存流中。
您需要写入请求流:
using (var ms=new MemoryStream()) request.GetRequestStream().CopyTo(ms);