MathNet和Octave计算正态方程之间的差异

时间:2015-04-28 08:59:00

标签: octave mathnet

好的,所以这是我使用c#& amp;计算正态方程的代码。 MathNet:

using System;
using System.Collections.Generic;
using System.Collections.ObjectModel;
using MathNet.Numerics.LinearAlgebra;
using MathNet.Numerics.LinearRegression;
using MathNet.Numerics.LinearAlgebra.Double;

namespace ConsoleApplication1
{
    public class NormalEquation
    {
        public void Calc()
        {
            var xData = new double[4, 5]{{1, 2104, 5,1,45}, {1, 1416,3,2,40}, {1,1534,3,2,30},{1,852,2,1,36}};

            var yData = new double[4, 1] { { 460 }, { 232 }, { 315 }, { 178 } };

            Matrix<double> X = Matrix<double>.Build.DenseOfArray(xData);

            Matrix<double> Y = Matrix<double>.Build.DenseOfArray(yData);

            var beta = X.Transpose().Multiply(X).Inverse().Multiply(X.Transpose().Multiply(Y));

            foreach (double d in beta.Enumerate())
            {
                Console.WriteLine("{0}\t", d);
            }
        }
    }

    class Program
    {
        static void Main()
        {

            NormalEquation n = new NormalEquation();
            n.Calc();
        }
    }
}

我的八度:

X=[1 2104 5 1 45; 1 1416 3 2 40;1 1534 3 2 30; 1 852 2 1 36 ]
y=[460; 232; 315; 178]
beta= pinv(X'*X)*(X'*y)

有人可以帮助我理解为什么 -

MathNet结果为:beta = {240,0.125,96,-56,-9}

Octave结果为:beta = {188.40032,0.38663,-56.13825,-92.96725,-3.73782}

1 个答案:

答案 0 :(得分:0)

方阵X'*X几乎是单数。输入

X=[1 2104 5 1 45; 1 1416 3 2 40;1 1534 3 2 30; 1 852 2 1 36 ];
det(X'*X)

产量

ans =   3.4192e-007