表1
ID Department Date
555 67 2015-04-28
111 58 2015-04-28
000 45 2015-04-28
表2
ID DEpartment Category
888 16 test
0001 16 test
如果我必须传入参数值table1.department = 16,我该如何创建存储过程它必须从table1中检索所有记录,但如果id在表2中,则必须忽略该记录。
如果我传递参数table1.department = 16 ,预期输出
输出
select *
from table1 as t1 inner join table2 as t2 on t1.ID=t2.ID
where t1.department='16'
id 555应该被忽略。
尝试了什么
from itertools import tee
def unpack_args(fn):
return lambda t: fn(*t)
def separate(fn, lx):
return map(
unpack_args(
lambda i, ly: filter(
lambda el: bool(i) == fn(el),
ly)),
enumerate(tee(lx, 2)))
答案 0 :(得分:2)
此查询将返回您想要的结果
SELECT Table1.ID,
Table1.Dept,
Table1.Category
FROM table1 WHERE Table1.ID NOT IN (SELECT Table2.ID FROM table2)