Question

我在Codeigniter开发了一个应用程序，一切都很顺利，但我有一个问题如下：
首次登录前端和后端后，我想在仪表板上实施autologin 说明：
当我第一次登录admin side时，会转到admin dashboard并关闭tab/browser而不点击logout button并将admin链接转到管理信息中心没有再次登录，到目前为止一切进展顺利，但是当我放front end link (after first time login and closing tab)时它没有进入admin仪表板并显示错误，如

页面未正确重定向

我在前端遇到同样的问题我想这样做是因为这是客户要求请帮我解决这个问题。感谢。

这是我的索引函数

if($_COOKIE['AS_AD_SES_ADMIN_ID']!='' && $_COOKIE['stay_signedin']=='1')
{
        $username = $_COOKIE['ADMIN_USERNAME'];
        $password = $_COOKIE['ADMIN_PASS'];

        $result = $this->verifylogin->login($username, $password);

        foreach($result as $row)
        {
            $sess_array = array(
                     'AS_AD_SES_ADMIN_ID'           =>  $row->fld_id,
                     'AS_AD_SES_ADMIN_FULL_NAME'    =>  $row->fld_user_name,
                     'AS_AD_SES_ADMIN_NAME'         =>  $row->fld_adm_name,
                     'AS_AD_SES_LOGIN_TIME'         =>  date('h:i:s A'),
                     'AS_AD_SES_LOGIN_DATE'         =>  date("d-m-Y"),
                     'AS_SES_ACCESS_LEVEL'          =>  $row->fld_access_level,
                     'AS_TAB_TITLE'                 =>  'Welcome to Project',
                     'logged_in'                    =>  TRUE
                   );

            $this->session->set_userdata($sess_array);
        }
        $this->load->view('dashboard');
}else{
        redirect(base_url());
}

Verifylogin模型的登录功能如下

function login($username, $password)
{
    $ip_address=$_SERVER['REMOTE_ADDR'];

    $this -> db -> select('fld_id, fld_user_name,fld_adm_name,fld_adm_pwd,fld_access_level');
    $this -> db -> from('tbl_admin');
    $this -> db -> where('fld_user_name',$username);
    $query = $this -> db -> get();

    if($query -> num_rows() == 1)
    {
        $res = $query->row();
        $pass = $res->fld_adm_pwd; 
        $pass1 = $this->encrypt->decode($pass); 
        if($pass1 == $password)
        {
            $password = $pass;

            $query = $this->db->query("SELECT fld_id,fld_user_name,fld_adm_name,fld_access_level,fld_adm_pwd,fld_stay_signed_in FROM tbl_admin where fld_user_name = '".$username."' and fld_adm_pwd = '".trim($password)."' and fld_isdeleted !=1 and fld_status = 'Active'");

            if($query->num_rows() == 1)
            {
              return $query->result();
            }
        }
        else
        {
            return false;
        }
    }

}

Answer 1

我认为问题是当浏览器关闭时$ cookie正在消耗，我建议使用$ _SESSION变量。

// Start the session
session_start();

 if($_SESSION['AS_AD_SES_ADMIN_ID']!='' && $_SESSION['stay_signedin']=='1')
        {
            $username = $_SESSION['ADMIN_USERNAME'];
            $password = $_SESSION['ADMIN_PASS'];

            $result = $this->verifylogin->login($username, $password);

            foreach($result as $row)
            {
                $sess_array = array(
                         'AS_AD_SES_ADMIN_ID'           =>  $row->fld_id,
                         'AS_AD_SES_ADMIN_FULL_NAME'    =>  $row->fld_user_name,
                         'AS_AD_SES_ADMIN_NAME'         =>  $row->fld_adm_name,
                         'AS_AD_SES_LOGIN_TIME'         =>  date('h:i:s A'),
                         'AS_AD_SES_LOGIN_DATE'         =>  date("d-m-Y"),
                         'AS_SES_ACCESS_LEVEL'          =>  $row->fld_access_level,
                         'AS_TAB_TITLE'                 =>  'Welcome to Project',
                         'logged_in'                    =>  TRUE
                       );

                $this->session->set_userdata($sess_array);
            }
            $this->load->view('dashboard');
        }else{
            redirect(base_url());
        }

Answer 2

如果您的verifylogin->login函数返回false，那么您也正在加载仪表板视图。您需要检查它是否返回错误或结果。并且你不需要foreach来获得单一结果。

if($_COOKIE['AS_AD_SES_ADMIN_ID']!='' && $_COOKIE['stay_signedin']=='1')
{
    $username = $_COOKIE['ADMIN_USERNAME'];
    $password = $_COOKIE['ADMIN_PASS'];

    $row = $this->verifylogin->login($username, $password);

    if($row)
    {
        $sess_array = array(
                 'AS_AD_SES_ADMIN_ID'           =>  $row->fld_id,
                 'AS_AD_SES_ADMIN_FULL_NAME'    =>  $row->fld_user_name,
                 'AS_AD_SES_ADMIN_NAME'         =>  $row->fld_adm_name,
                 'AS_AD_SES_LOGIN_TIME'         =>  date('h:i:s A'),
                 'AS_AD_SES_LOGIN_DATE'         =>  date("d-m-Y"),
                 'AS_SES_ACCESS_LEVEL'          =>  $row->fld_access_level,
                 'AS_TAB_TITLE'                 =>  'Welcome to Project',
                 'logged_in'                    =>  TRUE
               );

        $this->session->set_userdata($sess_array);
        $this->load->view('dashboard');
    }else{
        redirect(base_url());
    }
}else{
    redirect(base_url());
}


function login($username, $password)
{
    $ip_address=$_SERVER['REMOTE_ADDR'];

    $this -> db->select('fld_id, fld_user_name,fld_adm_name,fld_adm_pwd,fld_access_level');
    $this -> db -> from('tbl_admin');
    $this -> db -> where('fld_user_name',$username);
    $query = $this -> db -> get();

    if($query -> num_rows() == 1)
    {
        $res = $query->row();
        $pass = $res->fld_adm_pwd; 
        $pass1 = $this->encrypt->decode($pass); 
        if($pass1 == $password)
        {
            $password = $pass;

            $query = $this->db->query("SELECT fld_id,fld_user_name,fld_adm_name,fld_access_level,fld_adm_pwd,fld_stay_signed_in FROM tbl_admin where fld_user_name = '".$username."' and fld_adm_pwd = '".trim($password)."' and fld_isdeleted !=1 and fld_status = 'Active'");

            if($query->num_rows() == 1)
            {
              return $query->row();
            }
        }
    }
    return false;
}

Codeigniter Cookie后端和前端侧问题

2 个答案: