Question

我有一个谷歌地图链接，如下所示：

https://www.google.com/maps/place/Space+Needle/@47.620506,-122.349277,17z/data=!4m6!1m3!3m2!1s0x5490151f4ed5b7f9:0xdb2ba8689ed0920d!2sSpace+Needle!3m1!1s0x5490151f4ed5b7f9:0xdb2ba8689ed0920d

如何从PHP或Javascript中提取坐标以获取数组：

{47.620506, -122.349277}

Answer 1

如果您没有使用api（这是不可取的），您可以将页面放入一个字符串，并从内部提取长/ lat ...它在页面上多次给出作为参数echo $myArray['id']; // 1 ...我对正则表达式不太了解，所以我将使用ll

给出一个示例

strstr

Answer 2

这是我目前在网页上使用的代码。它也很容易做到。

 <div id="map-canvas">

            <script>
            function initialize() {

                var myLatlng;
                var mapOptions = {
                    zoom: 13,
                    mapTypeId: google.maps.MapTypeId.ROADMAP
                }
                var map = new google.maps.Map(document.getElementById("map-canvas"), mapOptions);

                if (navigator.geolocation) {
                    navigator.geolocation.getCurrentPosition(function(position) {

                        //User Location
/* This is the cords */ myLatlng = new google.maps.LatLng(position.coords.latitude, position.coords.longitude);

    //So if you want them individually just use position.coords.l... 
    //Please feel free to ask questions

    }

    google.maps.event.addDomListener(window, 'load', initialize);
    </script>
    </div>

Answer 3

如果您使用php，那么使用Google将识别的任何地址查询地图api非常容易：

$address = 'Space+Needle';
$url = "http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
$response = curl_exec($ch);
curl_close($ch);
$result = json_decode($response);
$ltlg = array($result->results[0]->geometry->location->lat, $result->results[0]->geometry->location->lng);

希望这有帮助

Answer 4

试试这个：

    public function getCoordinatesAttribute() {
        $url = "https://www.google.com/maps/place/Space+Needle/@47.620506,-122.349277,17z/data=!4m6!1m3!3m2!1s0x5490151f4ed5b7f9:0xdb2ba8689ed0920d!2sSpace+Needle!3m1!1s0x5490151f4ed5b7f9:0xdb2ba8689ed0920d";
        $url_coordinates_position = strpos($url, '@')+1;
        $coordinates = [];

        if ($url_coordinates_position != false) {
            $coordinates_string = substr($url, $url_coordinates_position);
            $coordinates_array = explode(',', $coordinates_string);

            if (count($coordinates_array) >= 2) {
                $longitude = $coordinates_array[0];
                $latitude = $coordinates_array[1];

                $coordinates = [
                    "longitude" => $longitude,
                    "latitude" => $latitude
                ];
            }

            return $coordinates;
        }

        return $coordinates;
    }

就我而言，我必须确保链接是谷歌地图位置 URL，因为这完全取决于网址中的字符“@”。

如何从Google Maps链接（PHP或Javascript）中提取坐标

4 个答案: