如何简化嵌套的sinatra路线？

Question

我在sinatra应用程序中需要嵌套子目录，如何简化这些重复代码？

# ------------- SUB1 --------------
get "/:theme/:sub1/?" do
    haml :"pages/#{params[:theme]}/#{params[:sub1]}/index"
end

# ------------- SUB2 --------------
get "/:theme/:sub1/:sub2/?" do
    haml :"pages/#{params[:theme]}/#{params[:sub1]}/#{params[:sub2]}/index"
end

# ------------- SUB3 --------------
get "/:theme/:sub1/:sub2/:sub3/?" do
    haml :"pages/#{params[:theme]}/#{params[:sub1]}/#{params[:sub2]}/#{params[:sub3]}/index"
end

# ------------- SUB4 --------------
get "/:theme/:sub1/:sub2/:sub3/:sub4/?" do
    haml :"pages/#{params[:theme]}/#{params[:sub1]}/#{params[:sub2]}/#{params[:sub3]}/#{params[:sub4]}/index"
end

Answer 1

您可以使用splat参数：

get "/:theme/*/?" do
  haml "pages/#{params[:theme]}/#{params[:splat].to_s}/index".to_sym  
end