目前,此查询会排除报告中不包含标记的记录。有人可以帮我改变这个查询,以便返回所有记录,有或没有标签吗?
SELECT
cmsdocument.internaldocid,
cmsdocument.documentid,
cmsdocument.versionid,
cmsdocversion.title,
string_agg(cmstag.tagname, ',')
FROM
public.cmsobjecttag,
public.cmstag,
public.cmsdocument,
public.cmsdocversion,
public.cmsuser
WHERE
cmsobjecttag.tagid = cmstag.tagid AND
cmsobjecttag.objectid = cmsdocument.internaldocid AND
cmsdocument.internaldocid = cmsdocversion.internaldocid AND
cmsdocument.userid = cmsuser.userid AND
cmsdocversion.state = 'published' AND
cmsobjecttag.objecttype = '102'
GROUP BY
cmsdocument.internaldocid,
cmsdocument.documentid,
cmsdocument.versionid,
cmsdocversion.title;
答案 0 :(得分:2)
正如@notulysses评论的那样,你应该使用外连接。例如(未经测试):
SELECT
d.internaldocid,
d.documentid,
d.versionid,
dv.title,
string_agg(t.tagname, ',')
FROM
public.cmsdocument d
JOIN public.cmsdocversion dv ON d.internaldocid = dv.internaldocid AND dv.state = 'published'
JOIN public.cmsuser u ON d.userid = u.userid
LEFT JOIN public.cmsobjecttag ot ON d.internaldocid = ot.objectid AND ot.objecttype = '102'
LEFT JOIN public.cmstag t ON t.tagid = ot.tagid
GROUP BY
d.internaldocid,
d.documentid,
d.versionid,
dv.title;