Question

我试图从网站上抓取一些内容。我最终发现它需要cookie，所以我用guzzle cookie插件解决了这个问题。这很奇怪，因为我无法通过执行var_dump来获取内容，但如果我这样做，它将显示该页面的回声＆＃39;这让我觉得有一些动态数据调用，它可以获取数据。我已经习惯了gui但不确定我应该对待它吗？谢谢

如果我使用domcrawler，我会收到错误消息。

代码 -

   use Symfony\Bundle\FrameworkBundle\Controller\Controller;

   use Symfony\Component\DomCrawler\Crawler;

   use Guzzle\Http\Client;

   use Guzzle\Plugin\Cookie\CookiePlugin;

   use Guzzle\Plugin\Cookie\CookieJar\ArrayCookieJar;

   $cookiePlugin = new CookiePlugin(new ArrayCookieJar());

     $url =  'http://www.myurl.com';
    // Add the cookie plugin to a client
     $client = new Client();

     $client->get();

    $client->addSubscriber($cookiePlugin);

  // Send the request with no cookies and parse the returned cookies
  $client->get($url)->send();

// Send the request again, noticing that cookies are being sent
  $request = $client->get($url);

  $response = $request->send();

 var_dump($response);
 $crawler = new Crawler($response);

  foreach ($crawler as $domElement) {
  print $domElement->filter('a')->links();
   }

错误

    Expecting a DOMNodeList or DOMNode instance, an array, a   
  string,        or     null, but got "Guzzle\Http\Message\Response

Answer 1

试试这个：

<强> For Guzzle 5

$crawler = new Crawler($response->getBody()->getContents());

http://docs.guzzlephp.org/en/latest/http-messages.html#id2 http://docs.guzzlephp.org/en/latest/streams.html#creating-streams

<强> For Guzzle 3

$crawler = new Crawler($response->getBody());

http://guzzle3.readthedocs.org/http-client/response.html#response-body

<强>更新

使用getContents方法的Guzzle 5的基本用法。

include 'vendor/autoload.php';

use GuzzleHttp\Client;

$client = new Client();
echo $client->get('http://stackoverflow.com')->getBody()->getContents();

其余的都在doc（包括Cookie）。

Guzzle响应无法与Domcrawler（）一起使用

1 个答案: