我是快速语言的新手。我在这里看了一些关于在swift中解析Json的问题,但是我的问题与其他问题有些不同。 当我写/ cmd = login& params {' user':' username',' password':' pass'}它返回正确的数据。如何在swift中解决这个问题 我将用户名和密码作为json发送给url但是 它检索错误,这意味着"格式无效" 请帮我。 这是我尝试过的:
var url:NSURL = NSURL(string: "http://<host>?cmd=login")!
//var session = NSURLSession.sharedSession()
var responseError: NSError?
var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)
// var request:NSMutableURLRequest = NSMutableURLRequest(URL: url)
var response: NSURLResponse?
request.HTTPMethod = "POST"
let jsonString = "params={\"user\":\"username\",\"password\":\"pass\"}"
request.HTTPBody = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion:true)
request.setValue("application/json; charset=UTF-8", forHTTPHeaderField: "Content-Type")
// send the request
NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: &responseError)
// look at the response
if let httpResponse = response as? NSHTTPURLResponse {
println("HTTP response: \(httpResponse.statusCode)")
} else {
println("No HTTP response")
}
let task = NSURLSession.sharedSession().dataTaskWithRequest(request){
data, response, error in
if error != nil {
println("error=\(error)")
return
}
println("****response= \(response)")
let responseString = NSString(data: data, encoding: NSUTF8StringEncoding)
println("**** response =\(responseString)")
var err: NSError?
var json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers , error: &err) as? NSDictionary
}
task.resume()
答案 0 :(得分:4)
根据您的问题假设服务器期望的格式是这样的:
http://<host>?cmd=login¶ms=<JSON object>
在将JSON对象附加到查询字符串之前,您需要首先URL-encode以消除任何非法字符。
您可以这样做:
let jsonString = "{\"user\":\"username\",\"password\":\"pass\"}"
let urlEncoadedJson = jsonString.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())
let url = NSURL(string:"http://<host>?cmd=login¶ms=\(urlEncoadedJson)")
答案 1 :(得分:0)
你的json字符串无效,应该是:
let jsonString = "{\"user\":\"username\",\"password\":\"pass\"}"
至于请求,我认为GET
是你真正需要的:
var urlString = "http://<host>" // Only the host
let payload = "?cmd=login¶ms=" + jsonString // params goes here
urlString += payload
var url:NSURL = NSURL(string: urlString)!
// ...
request.HTTPMethod = "GET"
答案 2 :(得分:0)
让我们说url是
https://example.com/example.php?Name=abc&data= {&#34;类&#34;:&#34; 625&#34;&#34受试者#34;:&#34;英语&#34;}
在Swift 4中
let abc = "abc"
let class = "625"
let subject = "english"
let baseurl = "https://example.com/example.php?"
let myurlwithparams = "Name=\(abc)" + "&data=" +
"{\"class\":\"\(class)\",\"subject\":\"\(subject)\"}"
let encoded =
myurlwithparams.addingPercentEncoding(withAllowedCharacters:
.urlFragmentAllowed)
let encodedurl = URL(string: encoded!)
var request = URLRequest(url: encodedurl!)
request.httpMethod = "GET"
答案 3 :(得分:-1)
我认为您不需要按照自己的方式对JSON进行编码。下面应该有用。
let jsonString = "params={\"user\":\"username\",\"password\":\"pass\"}"
var url:NSURL = NSURL(string: "http://<host>?cmd=login&?\(jsonString)")!
//var session = NSURLSession.sharedSession()
var responseError: NSError?
var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)
// var request:NSMutableURLRequest = NSMutableURLRequest(URL: url)
var response: NSURLResponse?
request.HTTPMethod = "POST"