Question

我正在尝试检查我的数据库中是否存在表，但我总是得到“你在！”作为输出。 if语句的输出未显示在浏览器中。

我感谢任何帮助。

  $con = new mysqli ( 'localhost', 'root', '', 'bustracker' );
    echo "You are in!";
             if($con->connect_errno){
        die ( "connection problem!".$con->connect_error);
             }

          //check whether route's table exists.
          $results = $con->query("SHOW TABLES LIKE '".$route."'");

           if( ($results->num_rows) == 1){
             echo "Table exist";
           }else{
            echo "table does not exist";
           }

Answer 1

SELECT 1 FROM tablename LIMIT 1;

如果没有错误，则表格存在。

或者，如果您想要正确，请使用INFORMATION_SCHEMA。

SELECT * 
FROM information_schema.tables
WHERE table_schema = 'yourdb' 
AND table_name = 'your_table_name'
LIMIT 1;

或者，您可以使用SHOW TABLES

SHOW TABLES LIKE 'your_table_name';

如果结果集中有一行，则表存在

Answer 2

Try this code it will definitely     work. simply copy and paste it. 

<?php 
    $con = @new mysqli('localhost', 'root', '', 'bustracker' );
    echo "You are in!";
    if ($con->connect_errno) {

        die ( "connection problem!".$con->connect_error);

             }
           else
           {
           $results = $con->query("SHOW TABLES LIKE '".$route."'");

           if( ($results->num_rows) == 1)
           {
             echo "Table exist";
           }
           else{
            echo "table does not exist";
           } 
           }
    ?>

检查表是否存在

2 个答案: