Question

我有两张表有博客帖子和其他没有观看表两者都是通过主键加入。

想要通过最大视图获取数据顺序。

views table -
post id    ip address
1           117.02.13.04
1           35.02.13.04 
1           86.02.13.04 
2           78.02.13.04
2           39.02.13.04

post table -
    ID   title
    1           abc
    2           cde
    3           fgh
    4           ijk
    5           asds

Answer 1

select * from post p 
left join 
(select post_id,count(ip_address) as count_views from views group by post_id ) v
on p.id=v.post_id ORDER BY v.count_views DESC

我建议您考虑不要使用带有空格的列名，例如ip address，这就是我在答案中使用ip_address的原因。

Answer 2

我认为这会对你有帮助 -

select count(views.post_id), posts.* from posts as posts left views as views on posts.id=views.post_id group by views.post_id order by views.post_id

Answer 3

  SELECT *, count(post id) as nos 
    FROM view table, post table  
   WHERE post id= id 
GROUP BY post id 
ORDER BY nos desc

对大多数视图的获取数据顺序的SQL查询

3 个答案: