我有一个名为PlayerScore
的表格,其中包含玩家名称及其平均分数:
Id Name Average
1 Sakib 80
2 Tamim 70
3 Mushfiq 60
4 Sabbir 50
5 Ashraful 20
6 Aftab 40
7 Rubel 30
8 Kalu 10
我想根据条件找到他们的合作伙伴关系, 平均分数大于40的palyer不能与得分低于40的球员合作。 我尝试了以下查询:
select a.Name,a.Average,b.Name,b.Average from ((select * from PlayerScore where Average<=40) as a inner join (select * from PlayerScore where Average<=40) as b on a.Id < b.Id)
union
select a.Name,a.Average,b.Name,b.Average from ((select * from PlayerScore where Average>=40) as a inner join (select * from PlayerScore where Average>=40) as b on a.Id < b.Id)
导致:
Name Average Name Average
Aftab 40 Kalu 10
Aftab 40 Rubel 30
Ashraful 20 Aftab 40
Ashraful 20 Kalu 10
Ashraful 20 Rubel 30
Mushfiq 60 Aftab 40
Mushfiq 60 Sabbir 50
Rubel 30 Kalu 10
Sabbir 50 Aftab 40
Sakib 80 Aftab 40
Sakib 80 Mushfiq 60
Sakib 80 Sabbir 50
Sakib 80 Tamim 70
Tamim 70 Aftab 40
Tamim 70 Mushfiq 60
Tamim 70 Sabbir 50
他们的任何解决方案都没有使用UNION
答案 0 :(得分:2)
select distinct a.Name,a.Average,b.Name,b.Average
from PlayerScore a
join PlayerScore b
on a.Id < b.Id
and ( a.Average<=40 and b.Average<=40
or a.Average>=40 and b.Average>=40
)
它可能会产生相同的计划。
答案 1 :(得分:1)
也许你可以这样做:
SELECT
t.*,
t2.*
FROM
PlayerScore AS t
CROSS JOIN PlayerScore AS t2
WHERE t.Average>=40 AND t2.Average<40
ORDER BY t.Name
答案 2 :(得分:0)
您可以根据条件创建2个组,并为它们提供不同的值,然后根据该值进行连接。这样的事情。
;WITH PlayerScore as
(
SELECT 1 AS Id,'Sakib' AS Name,80 AS Average
UNION ALL SELECT 2,'Tamim',70
UNION ALL SELECT 3,'Mushfiq',60
UNION ALL SELECT 4,'Sabbir',50
UNION ALL SELECT 5,'Ashraful',20
UNION ALL SELECT 6,'Aftab',40
UNION ALL SELECT 7,'Rubel',30
UNION ALL SELECT 8,'Kalu',10
),PlayerCriteria AS
(
SELECT *,CASE WHEN Average >= 40 THEN 1 ELSE 0 END joincondition
FROM PlayerScore
)
SELECT * FROM PlayerCriteria C1
INNER JOIN PlayerCriteria C2 ON C1.joincondition = C2.joincondition
AND C1.Id > C2.Id