我有一张这样的表
外国人表:
select * from table1
ID......NameIds
-------------------
1 ......1, 2 (its comma separated values)
主要表格(表格2)
ID Name
-------------------
1 Cleo
2 Smith
我想将表1显示为(我需要SQL函数或查询)
ID......NameIds
-------------------
1........Cleo, smith (show text/Name instead of values)
答案 0 :(得分:1)
正如评论中所述 - 您应该重新考虑您的表格设计,但尝试为此编写查询非常有趣:
SELECT T1.ID, NameID, Name
INTO #Temporary
FROM #Table1 AS T1
CROSS APPLY (
SELECT CAST(('<X>' + REPLACE(T1.NameIDs, ',', '</X><X>') + '</X>') AS XML)
) AS X(XmlData)
CROSS APPLY (
SELECT NameID.value('.', 'INT')
FROM XmlData.nodes('X') AS T(NameID)
) AS T(NameID)
INNER JOIN #Table2 AS T2
ON T2.ID = T.NameID
SELECT ID, STUFF(T.Names, 1, 1, '') AS Names
FROM #Table1 AS T1
CROSS APPLY (
SELECT ',' + Name
FROM #Temporary AS T
WHERE T.ID = T1.ID
ORDER BY T.NameID
FOR XML PATH('')
) AS T(Names)
<强>结果:强>
ID Names
--------------
1 Cleo,Smith
它做什么,它将您的逗号分隔列表拆分为行,将它们连接到NameID,然后再次连接它们。猜猜那有多高效? 它可能不是最好的方法,但它确实有效。