Question

我正在开发youtube api并开发一个youtube api网站，我想获得视频列表的下一页令牌，但我从xml feed获取数据。

如何从xml Feed获取下一页令牌？

这是我的代码：

<?php
// set feed URL
$feedURL = 'http://gdata.youtube.com/feeds/api/standardfeeds/most_viewed';

// read feed into SimpleXML object
$sxml = simplexml_load_file($feedURL);
?>
<h1><?php echo $sxml->title; ?></h1>
<?php
// iterate over entries in feed
foreach ($sxml->entry as $entry) {
  // get nodes in media: namespace for media information
  $media = $entry->children('http://search.yahoo.com/mrss/');

  // get video player URL
  $attrs = $media->group->player->attributes();
  $watch = $attrs['url']; 

  // get video thumbnail
  $attrs = $media->group->thumbnail[0]->attributes();
  $thumbnail = $attrs['url']; 

  // get <yt:duration> node for video length
  $yt = $media->children('http://gdata.youtube.com/schemas/2007');
  $attrs = $yt->duration->attributes();
  $length = $attrs['seconds']; 

  // get <yt:stats> node for viewer statistics
  $yt = $entry->children('http://gdata.youtube.com/schemas/2007');
  $attrs = $yt->statistics->attributes();
  $viewCount = $attrs['viewCount']; 

  // get <gd:rating> node for video ratings
  $gd = $entry->children('http://schemas.google.com/g/2005'); 
  if ($gd->rating) {
    $attrs = $gd->rating->attributes();
    $rating = $attrs['average']; 
  } else {
    $rating = 0; 
  }
  $my_format = 'mqdefault.jpg'; 
  $my_url = 'img.ytapi.com';
  ?>
  <div class="item">
    <span class="title">
      <a href="<?php echo $watch; ?>"><?php echo $media->group->title; ?></a>
    </span>
    <p>
      <span class="thumbnail">
        <a href="<?php echo $watch; ?>"><img src="<?php echo str_replace(array("i.ytimg.com","0.jpg"),array($my_url, $my_format), $thumbnail);?>" /></a>
        <br/>click to view
      </span> 
      <span class="attr">By:</span> <?php echo $entry->author->name; ?> <br/>
      <span class="attr">Duration:</span> <?php printf('%0.2f', $length/60); ?> 
      min. <br/>
      <span class="attr">Views:</span> <?php echo $viewCount; ?> <br/>
      <span class="attr">Rating:</span> <?php echo $rating; ?> 
    </p>
  </div>      
<?php
}
?>

Answer 1

您可以使用start-index参数请求其他页面。此参数与max-results参数一起使用。所以：

如果省略max-results参数，请申请以下网址：

http://gdata.youtube.com/feeds/api/standardfeeds/most_viewed
结果1-25
http://gdata.youtube.com/feeds/api/standardfeeds/most_viewed?start-index=26
结果26-50
http://gdata.youtube.com/feeds/api/standardfeeds/most_viewed?start-index=51
结果51-75

如果您设置了max-results=10，请申请以下网址：

我可以使用xml从youtube api获取页面令牌吗？

1 个答案: