即使我创建了一个帐户来测试登录,我仍然在我的Ember-Firebase应用中收到错误“指定的电子邮件地址无效”。
我想知道它是否与我将信息作为字符串传递的方式有关?
初始化/ emberfire.js
import Ember from 'ember';
import Firebase from 'firebase';
var session = Ember.Object.extend({
ref : new Firebase("https://nutella.firebaseio.com"),
addFirebaseCallback: function() {
var session = this;
var isNewUser = true;
this.get("ref").onAuth(function(authData) {
if (authData) {
session.set("isAuthenticated", true);
} else if (authData && isNewUser) {
session.get("ref").child("users").child(authData.uid).set({
provider: authData.provider,
name: getName(authData)
});
} else {
session.set("isAuthenticated", false);
}
});
}.on("init"),
createUser: function() {
var session = this;
return new Ember.RSVP.Promise(function(resolve, reject) {
session.get('ref').createUser({
name: "",
email: "",
password: ""
},
function(error, userData) {
if (userData) {
resolve(userData.uid);
session.set("isNewUser", true);
} else {
reject(error);
}
});
});
},
的application.js
import Ember from 'ember';
import Firebase from 'firebase';
var ref = new Firebase("https://nutella.firebaseio.com");
export default Ember.Route.extend({
actions: {
createUser: function() {
var controller = this;
controller.get('session').createUser().then(function(user) {
}, function() {
});
},
如果你能指出我正确的方向,我真的很感激!
答案 0 :(得分:0)
传递字符串应该不是问题。以下是一些建议:
LOCAL_PATH := $(call my-dir)
#leptonica
LEPTONICA_LOCAL := $(LOCAL_PATH)/com_googlecode_leptonica_android
LEPTONICA_PATH := $(LEPTONICA_LOCAL)/src
include $(CLEAR_VARS)
LOCAL_MODULE := liblept
LOCAL_SRC_FILES := ../libs/$(TARGET_ARCH_ABI)/liblept.so
LOCAL_EXPORT_C_INCLUDES := \
$(LEPTONICA_LOCAL) \
$(LEPTONICA_PATH)/src
include $(PREBUILT_SHARED_LIBRARY)
#tesseract
TESSERACT_LOCAL := $(LOCAL_PATH)/com_googlecode_tesseract_android
TESSERACT_PATH := $(TESSERACT_LOCAL)/src
include $(CLEAR_VARS)
LOCAL_MODULE := libtess
LOCAL_SRC_FILES := ../libs/$(TARGET_ARCH_ABI)/libtess.so
LOCAL_EXPORT_C_INCLUDES := \
$(LOCAL_PATH) \
$(TESSERACT_PATH)/api \
$(TESSERACT_PATH)/ccmain \
$(TESSERACT_PATH)/ccstruct \
$(TESSERACT_PATH)/ccutil \
$(TESSERACT_PATH)/classify \
$(TESSERACT_PATH)/cube \
$(TESSERACT_PATH)/cutil \
$(TESSERACT_PATH)/dict \
$(TESSERACT_PATH)/opencl \
$(TESSERACT_PATH)/neural_networks/runtime \
$(TESSERACT_PATH)/textord \
$(TESSERACT_PATH)/viewer \
$(TESSERACT_PATH)/wordrec \
$(LEPTONICA_PATH)/src \
$(TESSERACT_LOCAL)
LOCAL_SHARED_LIBRARIES := liblept
include $(PREBUILT_SHARED_LIBRARY)
#opencv
include $(CLEAR_VARS)
OPENCV_PACKAGE_DIR:= /Users/danielsierraf/Documents/OpenCV-2.4.10-android-sdk/sdk
OPENCV_CAMERA_MODULES := off
include $(OPENCV_PACKAGE_DIR)/native/jni/OpenCV.mk
LOCAL_MODULE := run_detection
LOCAL_SRC_FILES := text_detect.cpp android.cpp
LOCAL_LDLIBS += -landroid -llog -ldl
LOCAL_SHARED_LIBRARIES += libtess liblept
include $(BUILD_SHARED_LIBRARY)
:createUser
session.get('ref').createUser({
name: "",
email: "",
password: ""
},
一个额外的参数Firebase.createUser()
。在.createUser()
documentation中,参数列为:
name
对象
包含与新用户帐户对应的电子邮件和密码属性的对象。
credentials
功能
创建用户帐户时将调用的回调函数。失败时,第一个参数将是一个表示失败的Error对象,具有机器可读的代码属性。成功时,第一个参数将为null,第二个参数将是包含新创建用户的属性的对象,包括uid。
所以,这是您对onComplete
的调用的修订版本:
createUser()
如果没有这样做,你能否提供更多信息 - 你在哪里(行号)收到错误?
希望有所帮助。