Question

我有一个测试类，试图通过NSURLConnection访问Google。如果我尝试将其设为泛型，则永远不会调用NSURLConnectionDataDelegate方法。

class Remote<T: NSObject>: NSObject, NSURLConnectionDelegate, NSURLConnectionDataDelegate {
//class Remote: NSObject, NSURLConnectionDelegate, NSURLConnectionDataDelegate {

    var data = NSMutableData()

    func connect(query:NSString) {
        var url =  NSURL(string:"http://www.google.com")!
        var request = NSURLRequest(URL: url)
        var conn = NSURLConnection(request: request, delegate: self, startImmediately: true)
    }


    func connection(didReceiveResponse: NSURLConnection!, didReceiveResponse response: NSURLResponse!) {
        LF.log("didReceiveResponse")
    }

    func connection(connection: NSURLConnection!, didReceiveData conData: NSData!) {
        LF.log("didReceiveData")
        self.data.appendData(conData)
    }

    func connectionDidFinishLoading(connection: NSURLConnection!) {
        LF.log("didFinished")
        //println(self.data)
    }


    deinit {
        println("deiniting")
    }
}

测试它（评论/取消注释要比较的第一行/第二行）：

    let remote = Remote<NSObject>()
    //let remote = Remote()
    remote.connect("")

请问好吗？

Update1：回答评论1，它是一个处理网络连接和解析的REST客户端。我之后写了一篇关于此的博客（因为它还处于开发阶段），但是为了给你这个想法，我的项目中有一些演示代码：

        let client = ICRestClient<ICCategoryModel>(api:IC.api.category_list)
        client.func_array = {
            (results: [ICCategoryModel]?, error: NSError?) -> Void in
            block!(results, error)
        }
        client.execute()

ICCategoryModel就像：

class ICSubCategoryModel: ICModel {
    var name: String?
    var category_id: Int = 0
}

这个想法是你传递了API URL，你得到一个带有一些反射对象而不是Dictionary的数组（或错误）。它来自我的LSwift库，支持各种身份验证方法（buildin-parameters，cookie，header，authentication challenge等）。

Answer 1

其中一个问题是我无法访问class LRestConnectionDelegate: NSObject { var func_done: ((NSURLResponse?, NSData!, NSError!) -> Void)? var credential: NSURLCredential? var response: NSURLResponse? var data: NSMutableData = NSMutableData() func connection(connection: NSURLConnection, willSendRequestForAuthenticationChallenge challenge: NSURLAuthenticationChallenge) { if challenge.previousFailureCount > 0 { challenge.sender.cancelAuthenticationChallenge(challenge) } else if let credential = credential { challenge.sender.useCredential(credential, forAuthenticationChallenge:challenge) } else { LF.log("REST connection will challenge", connection) } } func connection(connection: NSURLConnection, didReceiveResponse a_response: NSURLResponse) { //LF.log("CONNECTION response", response) response = a_response } func connection(connection: NSURLConnection, didReceiveData data_received: NSData) { //LF.log("CONNECTION data", data.length) data.appendData(data_received) } func connectionDidFinishLoading(connection: NSURLConnection) { //LF.log("CONNECTION finished", connection) if func_done != nil { func_done!(response, data, nil) } } func connection(connection: NSURLConnection, didFailWithError error: NSError) { //LF.log("CONNECTION failed", error) if let func_done = func_done { func_done(response, nil, error) } } deinit { //LF.log("DELEGATE deinit", self) } }的委托对象。我通过创建另一个非泛型类型的RemoteDelegate类来提出解决方案，并将其设置为“conn”的委托。它现在有效，但它只是一个解决方法，我仍然在寻找问题的答案。

我的代表班：

class LRestClient<T: LFModel>

这适用于let delegate = LRestConnectionDelegate() delegate.credential = credential delegate.func_done = func_done connection = NSURLConnection(request:request, delegate:delegate, startImmediately:true)：

@Override
    public void onClick(View v) {
        // TODO Auto-generated method stub

        if (mInterstitialAd.isLoaded()) {
            mInterstitialAd.show();
        }

        switch(v.getId())
        {
            case R.id.troop_button:
                gotoTroopScreen();
                break;
        }
    }


public void gotoTroopScreen()
{
    Intent intent = new Intent(this, troop.class);
    startActivity(intent);
}

Answer 2

因为您正在同步使用NSURLConnection，所以必须在主运行循环中安排操作。将以下代码添加到connect函数的末尾：

conn?.scheduleInRunLoop(NSRunLoop.currentRunLoop, forMode: NSDefaultRunLoopMode)

或者，将startImmediately设为NO并致电conn?.start()。

NSURLConnection委托方法在通用类中不调用

2 个答案: