我知道您可以通过向**kwargs
提供filter_by
来为SQLAlchemy的查询构建动态过滤器。
例如
filters = {'id': '123456', 'amount': '232'}
db.session.query(Transaction).filter_by(**filters)
以下是我的问题:
如果我需要查询“大于”或“小于”条款,该怎么办? 例如(原始SQL):
select * from transaction t
where t.amount > 10 and t.amount < 100;
答案 0 :(得分:16)
我建议您使用filter_by
而不是filter
,而是为您提供更多选择。
例如(来自手册):
db.session.query(MyClass).filter(
MyClass.name == 'some name',
MyClass.id > 5,
)
就你的情况而言:
filters = (
Transaction.amount > 10,
Transaction.amount < 100,
)
db.session.query(Transaction).filter(*filters)
答案 1 :(得分:2)
def get_filter_by_args(dic_args: dict):
filters = []
for key, value in dic_args.items(): # type: str, any
if key.endswith('___min'):
key = key[:-6]
filters.append(getattr(model_class, key) > value)
elif key.endswith('___max'):
key = key[:-6]
filters.append(getattr(model_class, key) < value)
elif key.endswith('__min'):
key = key[:-5]
filters.append(getattr(model_class, key) >= value)
elif key.endswith('__max'):
key = key[:-5]
filters.append(getattr(model_class, key) <= value)
else:
filters.append(getattr(model_class, key) == value)
return filters
dic_args = {
'is_created': 1,
'create_time__min': 1588125484029,
}
filters = get_filter_by_args(dic_args)
lst = session.query(model_class).filter(*filters)