以下是我的文档样本,名为products:
{
"_id" : "B000KIT6LQ",
"brand" : "unknown",
"category" : "Electronics",
"price" : "11.99",
"title" : "Scosche KA2067B 2005..."
"reviews" : [
{
"date" : ISODate("1969-12-31T23:59:59Z"),
"score" : 5,
"user_id" : "AK7M5Y7E9O3L7",
"sentiment" : 0.5,
"text" : "Bought this so I ...",
"user_gender" : "female",
"voted_total" : 0,
"voted_helpful" : 0,
"user_name" : "Alex",
"summary" : "It is what it is"
},
{
"date" : ISODate("1969-12-31T23:59:59Z"),
"score" : 5,
"user_id" : "A26VRLMPEA8IDR",
"sentiment" : 0.352,
"text" : "Years ago I worked as an...",
"user_gender" : "male",
"voted_total" : 0,
"voted_helpful" : 0,
"user_name" : "Jack R. Smith",
"summary" : "Great Kit"
},
{
"date" : ISODate("1969-12-31T23:59:59Z"),
"score" : 4,
"user_id" : "A1TGBDVX3QXCRH",
"sentiment" : 0.19318181818181818,
"text" : "This insert works great in my ...",
"user_gender" : "female",
"voted_total" : 0,
"voted_helpful" : 0,
"user_name" : "J. Reed",
"summary" : "Fits great in my 2006 Spectra5"
}
]
}
我有很多类别的文件。我正在尝试创建一个mongo查询,这将导致所有类别的评论数量(子文档)每年。我必须按类别和年份分组,并获得评论数量的计数。 这是我到目前为止的查询:
db.products.aggregate([
{ $unwind : "$reviews" },
{ $group: {
_id: {category: "$category", date: "$reviews.date.getFullYear()"},
count: { $sum: 1 }}},
{$sort:{"count": -1}}
])
由于某种原因,getFullYear()方法对我不起作用。如果我按$reviews.date
分组,我会得到结果。
任何关于获得正确查询的指针都表示赞赏。
感谢
答案 0 :(得分:1)
您无法在汇总管道中使用getFullYear()
等JavaScript函数,您需要使用等效的aggregation Date operator,在本例中为$year
。
db.products.aggregate([
{ $unwind : "$reviews" },
{ $group: {
_id: {category: "$category", date: {$year: "$reviews.date"}},
count: { $sum: 1 }}},
{$sort:{"count": -1}}
])