Question

我在android中制作了一个简单的游戏，中间的精灵由4个按钮控制，我希望分配给该按钮的方法在按下时按相应的方向移动精灵，我已尝试在onCreate方法中执行此操作：

def times_table(times,factor):
    """takes two positive integers and returns a list of lists

    int, int -> list of lists"""
    table = [[0]*(factor+1)]
    for i in range(1,times+1):
        table.append(list(range(0,i*factor+1,i)))
    return table  


def print_table(listx):
    """takes a list of lists of numbers and displays them on the screen

    list of numbers -> numbers"""
    for x in listx:
        for y in x:
            print('{0:<10}'.format(y), end='')
        print()

number1 = int(input("What is the maximum value for the first factor?"))
number2 = int(input("What is the maximun value for the second factor?"))
print("Here is your times table:")
table = times_table(number1, number2)
print_table(table)

但是按下按钮时这只能工作一次。我希望在按下按钮时执行该方法，以及如何控制方法的更新时间。

Answer 1

boolean fingerDown = false;

button1.setOnTouchListener(new OnTouchListener() {

    @Override public boolean onTouch(View v, MotionEvent event){
        if(event.getAction == MotionEvent.ACTION_DOWN){
             fingerDown = true;
             move_sprite();
        } else if ( event.getAction() == MotionEvent.ACTION_UP ){
             fingerDown = false;
        } 
        return true;      
    }
});

public void move_sprite(){
    // in new thread, or handler,
       while(fingerDown){
          // do your thing
       }
}

在android中按下按钮时继续执行方法

1 个答案: