Question

我有这个代码用于从数据库中提取所有用户。此代码有效，并显示来自DB的所有用户

<?php

$sqlsel = "SELECT picture,username,email,configured,gender FROM members ORDER BY username";
$stmt = $mysqli->prepare($sqlsel);
$stmt->execute();
$stmt->bind_result($profpicture,$uname,$email,$confred,$gender);
while($stmt->fetch())
{
    if(empty($profpicture)){
    echo "<img src='profile_pictures/public_icon.png' width='50' height='50'><br>";}else {
                                        echo " <div class='img'><img  src='profile_pictures/".$profpicture."' alt='Profile Pic'></div><br>";
                                }
    echo "<b>Email:</b> ".$email."<br> ";

    if($gender == Woman){
        $gen = her;
    }
    else{
        $gen = his;
    }

      echo "<b>Username: </b>".$uname." </p> ";
if(empty($confred)){
    echo "<font color='#FF4747'>".$uname." has not configured ".$gen." account yet.</font>";
} else{
    echo "<form action='".$uname.".php'>
        <input type='submit' class='buttondiv' value='Visit ".$uname."&apos;s Profile'>
</form>";
}
    echo "<hr class='hr' />";

} 
?>

所以我做的几乎一样，但有帖子。它应该从数据库中提取所有帖子，但它只显示第一个...为什么？

<?php

$selectposts = "SELECT postby,posttxt,time FROM posts ORDER BY time";
$stmt = $mysqli->prepare($selectposts);
$stmt->execute();
$stmt->bind_result($postby,$posttxt,$posttime);
while($stmt->fetch()){
    $stmt->close();
    $stmt = $mysqli->prepare("SELECT picture FROM members WHERE username = ?");
        $stmt->bind_param('s', $postby);
        $stmt->execute();
        $stmt->bind_result($picture);
                        while ($stmt->fetch()){
                                if(empty($picture)){
                                        $profpicturefromdb = " <img src='profile_pictures/public_icon.png' width='25' height='25' class='fxdmimg'>";
                                } else {
                                        $profpicturefromdb = " <img width='25' class='fxdmimg' height='25' src='profile_pictures/".$picture."' alt='Profile Picture'>";
                             }
echo 
"<p><center><div class='postdv'> 
<b>".$profpicturefromdb." 
<h3>".$postby."</h3></b><font color='#000'>  
[ ".$posttime." ]</font><hr class='hr'>
<font color='#000'>".$posttxt."</font><hr class='hr'>
<form method='POST'>
<input type='submit' name='voteup' class='voteup' value='Up'> 
<input type='submit' name='votedown' class='votedown' value='Down'>
</form>
</center>
</div>";
}
}

?>

由于

Answer 1

这是因为您在$ stmt变量中重写了第一个查询结果。试试这个：

<?php

$selectposts = "SELECT postby,posttxt,time FROM posts ORDER BY time";
$stmt        = $mysqli->prepare($selectposts);
$stmt->execute();
$stmt->bind_result($postby, $posttxt, $posttime);
while ($stmt->fetch()) {
    $stmt1 = $mysqli->prepare("SELECT picture FROM members WHERE username = ?");
    $stmt1->bind_param('s', $postby);
    $stmt1->execute();
    $stmt1->bind_result($picture);
    while ($stmt1->fetch()) {
        if (empty($picture)) {
            $profpicturefromdb = " <img src='profile_pictures/public_icon.png' width='25' height='25' class='fxdmimg'>";
        } else {
            $profpicturefromdb = " <img width='25' class='fxdmimg' height='25' src='profile_pictures/" . $picture . "' alt='Profile Picture'>";
        }
        echo "<p><center><div class='postdv'>
            <b>" . $profpicturefromdb . "
            <h3>" . $postby . "</h3></b><font color='#000'>
            [ " . $posttime . " ]</font><hr class='hr'>
            <font color='#000'>" . $posttxt . "</font><hr class='hr'>
            <form method='POST'>
            <input type='submit' name='voteup' class='voteup' value='Up'>
            <input type='submit' name='votedown' class='votedown' value='Down'>
            </form>
            </center>
            </div>";
    }
}
$stmt->close();

?>

一个mysqli工作而另一个不工作..？

1 个答案: