Question

我创建了一个显示多个网页的应用。我希望该应用程序与whatsapp和其他IM信使分享在该网页上显示的图像，因为我已经添加了一个上下文菜单并已实施ACTION_SEND但它没有工作。当我尝试分享图片时，它会给我错误＆＃34;分享失败请再试一次＆＃34; 这是我的代码

public class TopRatedFragment extends Fragment {
private ProgressBar progress;
private WebView myWebView2;
private Menu optionsMenu;

public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {

    View rootView = inflater.inflate(R.layout.fragment_top_rated, container, false);


    String url = "http://images.google.com";
    myWebView2 = (WebView) rootView.findViewById(R.id.webViewTop);
    myWebView2.setWebChromeClient(new myWebViewClient());
    myWebView2.getSettings().setJavaScriptEnabled(true);
    progress = (ProgressBar) rootView.findViewById(R.id.progressBar3);
    progress.setMax(100);
    setHasOptionsMenu(true);
    myWebView2.loadUrl(url);


    myWebView2.setWebViewClient(new WebViewClient() {

        @Override
        public boolean shouldOverrideUrlLoading(WebView View, String url) {
            View.loadUrl(url);
            TopRatedFragment.this.progress.setProgress(0);
            return true;
        }
    });
    myWebView2.setOnKeyListener(new android.view.View.OnKeyListener() {
        @Override
        public boolean onKey(View v, int keyCode, KeyEvent event) {
            if (event.getAction() == KeyEvent.ACTION_DOWN) {
                WebView webView = (WebView) v;

                switch (keyCode) {
                    case KeyEvent.KEYCODE_BACK:
                        if (webView.canGoBack()) {
                            webView.goBack();
                            return true;
                        }
                        break;
                }
            }

            return false;
        }
    });
    return rootView;

}

@Override
public void onCreateOptionsMenu(
        Menu menu, MenuInflater inflater) {
    inflater.inflate(R.menu.menu_main, menu);
    optionsMenu = menu;
}


@Override
public boolean onOptionsItemSelected(MenuItem item) {
    // handle item selection
    switch (item.getItemId()) {
        case R.id.airport_menuRefresh:

            TopRatedFragment.this.myWebView2.reload();
            setRefreshActionButtonState(true);
            return true;
        default:
            return super.onOptionsItemSelected(item);
    }
}


@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo)
{
    super.onCreateContextMenu(menu, v, menuInfo);
    menu.add(0, v.getId(), 0, "Call");
    menu.add(0, v.getId(), 0, "share image");
}
@Override
public boolean onContextItemSelected(MenuItem item){
    if(item.getTitle()=="Call"){
        Toast.makeText(getActivity(), "calling code", Toast.LENGTH_LONG).show();
    }
    else if(item.getTitle()=="share image")
        {

       // This is the code which i am using for share intent
        Intent share = new Intent(android.content.Intent.ACTION_SEND);
        share.setType("image/*");
        share.putExtra(Intent.EXTRA_STREAM, Uri.parse(Environment.getExternalStorageState()));
        startActivity(Intent.createChooser(share, "Share image using"));
    }else{
        return false;
    }
    return true;
}

感谢您的帮助！

Answer 1

这条线看起来很奇怪

share.putExtra(Intent.EXTRA_STREAM, Uri.parse(Environment.getExternalStorageState()));

stream extra应该包含你想要分享的图像的uri，但是你将它设置为我甚至不理解它应该做什么的东西 - 甚至不能评估为uri。目前，您不会向意图提供有关您要发送的内容的任何信息。将流额外设置为图像位置uri，你应该没问题。

（顺便说一句，你真的应该使用equals（）而不是==来比较字符串。你不应该识别标题上的菜单项，因为它在本地化时会失败等。使用菜单项ID。）

将图像从webview共享到whatsapp

1 个答案: