Question

我有这个jquery ajax插件：

${project.build.finalName}

问题是：我需要将函数传递给参数onsuccess和onerror

类似于以下内容

(function ($) {
$.fn.Ajax_Data = function (Controller, Action, Data, onsuccess, onerror) {
    event.preventDefault();

        var options = {};
        options.url = "/" + Controller + "/" + Action;
        options.type = "POST";
        options.data = JSON.stringify(Data);
        options.dataType = "json";
        options.contentType = "application/json";
        options.success = onsuccess;
        options.error = onerror;

        $.ajax(options);
};
})(jQuery);

Answer 1

我被发现是一个很好的解决方案

以下

function onsuccess() { $('tr:eq(' + RowIndex + ')').remove(); };
function onerror() { alert('there is some thing wrong !!'); };

$(this).Ajax_Data("OnePageGrid", "Delete", { Id: CurrantID }, 
                 onsuccess(),
                 onerror());

Answer 2

我还得到了另一个解决方案它运作良好

$(this).Ajax_Data("OnePageGrid", "Delete", { Id: CurrantID }, 
{ onsuccess: document.getElementById("tblBlah").deleteRow(RowIndex) },
{ onerror:  alert('there is some thing wrong !!') });

如何将函数传递给ajax插件参数

2 个答案: