我有3张桌子。产品价格，发票产品和订购产品的表格。我正在尝试创建一个连接这些的视图。我想输出产品价格，共计发票产品和订购产品。
products_price
id season_id product_id product_price
1 1 1 3.99
2 1 2 6.99
3 1 3 5.99
4 1 4 5.99
....
invoices_products
id season_id invoice_id product_id piece_qty
1 1 1 1 1600
2 1 2 2 3200
3 1 3 2 200
4 1 4 1 120
....
orders_products
id season_id order_id product_id piece_qty
1 1 1 1 160
2 1 2 1 40
3 1 2 2 20
4 1 3 2 10
....
以下是我迄今为止尝试的View语句中的一些查询。
这个查询给了我想要的一切。 View的输出是完美的，但前两行的SUM（）是关闭的。对于第1行和第2行，total_invoice_product为双倍。total_order_product对于第1行为4x，对于第2行为3x。
声明1：
SELECT
`t1`.`id` AS `id`,
`t1`.`season_id` AS `season_id`,
`t1`.`product_id` AS `product_id`,
`t1`.`product_piece_price` AS `product_piece_price`,
SUM(`t2`.`piece_qty`) AS `total_invoice_product`,
SUM(`t3`.`piece_qty`) AS `total_order_product`
FROM
((`products_price` `t1`
LEFT JOIN `invoices_products` `t2` ON (((`t2`.`product_id` = `t1`.`product_id`)
AND (`t2`.`season_id` = `t1`.`season_id`))))
LEFT JOIN `orders_products` `t3` ON (((`t3`.`product_id` = `t1`.`product_id`)
AND (`t3`.`season_id` = `t1`.`season_id`))))
GROUP BY `t1`.`season_id` , `t1`.`product_id`
此查询为我提供了我期望的输出。它不是我想要的完整输出，但它对于声明是正确的。 SUM（）总数也是关于这个。
声明2：
SELECT
`t1`.`id` AS `id`,
`t1`.`season_id` AS `season_id`,
`t1`.`product_id` AS `product_id`,
`t1`.`product_price` AS `product_price`,
SUM(`t2`.`piece_qty`) AS `total_invoice_product`,
SUM(`t3`.`piece_qty`) AS `total_order_product`
FROM
((`products_price` `t1`
LEFT JOIN `invoices_products` `t2` ON ((`t2`.`product_id` = `t1`.`product_id`)))
LEFT JOIN `orders_products` `t3` ON ((`t3`.`product_id` = `t1`.`product_id`)))
WHERE
((`t2`.`season_id` = `t1`.`season_id`)
AND (`t2`.`product_id` = `t1`.`product_id`))
GROUP BY `t1`.`season_id` , `t1`.`product_id`
我想要的输出
id season_id product_id product_price total_invoice total_order
1 1 1 3.99 1720 200
2 1 2 6.99 3400 30
3 1 3 5.99 576
4 1 4 5.99 800
收到声明1的输出
id season_id product_id product_price total_invoice total_order
1 1 1 3.99 3440 800
2 1 2 6.99 6800 90
3 1 3 5.99 576
4 1 4 5.99 800
收到声明2的输出
id season_id product_id product_price total_invoice total_order
1 1 1 3.99 3440 800
2 1 2 6.99 6800 90
我可以像下面这样构建一个查询，它完美无缺。我得到了我需要的确切输出，但是这段代码不能用作视图。我收到此错误：错误1349：查看的SELECT包含FROM子句SQL语句中的子查询
完美查询，但不会作为视图
SELECT
products_price.id,
products_price.season_id,
products_price.product_id,
products_price.product_price,
invoices_grouped.total_invoice_product,
orders_grouped.total_order_product
FROM
products_price
LEFT JOIN
(SELECT
invoices_products.product_id,
invoices_products.season_id,
SUM(invoices_products.piece_qty) AS total_invoice_product
FROM
invoices_products
GROUP BY
invoices_products.product_id) AS invoices_grouped
ON
invoices_grouped.product_id = products_price.product_id
AND
invoices_grouped.season_id = products_price.season_id
LEFT JOIN
(SELECT
orders_products.product_id,
orders_products.season_id,
SUM(orders_products.piece_qty) AS total_order_product
FROM
orders_products
GROUP BY
orders_products.product_id) AS orders_grouped
ON
orders_grouped.product_id = products_price.product_id
AND
orders_grouped.season_id = products_price.season_id
我需要什么
我已经尝试过其他一些陈述。他们要么得到更糟糕的结果，要么相同。有人可以帮助我使用适当的SUM来处理语句1吗？
为问题编辑1
此视图提供的信息将被大量调用。 products_price和invcoices_products表不会经常更改。 orders_products将会发生很大变化。如果需要2个视图，那么使用＆＃34; Perfect＆＃34;会更有效吗？查询上面或使用2个视图？
编辑2以进行其他查询
这是我的视图声明中的另一个查询。此查询是上面显示的声明1 的一部分。此查询工作正常但不完整。我需要第二个SUM列。当你添加第二个LEFT JOIN时，它会打破SUM总数。
SELECT
`t1`.`id` AS `id`,
`t1`.`season_id` AS `season_id`,
`t1`.`product_id` AS `product_id`,
`t1`.`product_piece_price` AS `product_piece_price`,
SUM(`t2`.`piece_qty`) AS `total_invoice_product`
FROM
(`products_price` `t1`
LEFT JOIN `invoices_products` `t2` ON (((`t2`.`product_id` = `t1`.`product_id`)
AND (`t2`.`season_id` = `t1`.`season_id`))))
GROUP BY `t1`.`season_id` , `t1`.`product_id`
输出
id season_id product_id product_price total_invoice
1 1 1 3.99 1720
2 1 2 6.99 3400
3 1 3 5.99 576
4 1 4 5.99 800
答案 0 :(得分：0)
嗯，MySql有一些限制，所以你需要为子查询创建2个视图并使用它们：
create view viewInvoices
as
select season_id, product_id, sum(piece_qty) pq
from invoices_products group by season_id, product_id
create view viewOrders
as
select season_id, product_id, sum(piece_qty) pq
from orders_products group by season_id, product_id
select pp.id,
pp.season_id,
pp.product_id,
pp.product_price,
i.pq as total_invoice,
o.pq as total_order
from products_price pp
left join viewInvoices as i
on pp.season_id = i.season_id and pp.product_id = i.product_id
left join viewOrders as o
on pp.season_id = o.season_id and pp.product_id = o.product_id
答案 1 :(得分：0)
尝试此查询
SELECT * from products_price as a left join (select product_id, sum(piece_qty)total_invoices from invoices_products group by product_id) as b on a.product_id=b.product_id left join (select product_id, sum(piece_qty) as total_order from orders_products group by product_id) as c on a.product_id=c.product_id