Question

我使用LIKE关键字查询带有单个搜索参数的表格。当我在MySQL Workbench中运行以下sql语句时，它按预期正常工作。

SET @search = 'B'; 
SELECT T.*,D.divisionname 
FROM Township AS T INNER JOIN Division AS D ON T.divisionid=D.divisionid 
WHERE T.townshipcode LIKE CONCAT('%', @search, '%') OR 
T.townshipname LIKE CONCAT('%', @search, '%') OR 
D.divisionname LIKE CONCAT('%', @search, '%') 
ORDER BY T.townshipcode LIMIT 0,10

但是，当我使用JdbcTemplate执行我的java代码时，我得到了BadSqlGrammarException。以下是我的java代码：

public List<Township> getList(Integer pageNumber, Integer pageDisplayLength, String searchParameter) {
    int start = ((pageNumber - 1) * pageDisplayLength);
    String query = "";
    if (null != searchParameter && !searchParameter.equals("")){

        query = "SET @search = '" + searchParameter + "'; " +
                "SELECT T.*,D.divisionname FROM Township AS T " +
                "INNER JOIN Division AS D ON T.divisionid=D.divisionid " +
                "WHERE T.townshipcode LIKE CONCAT('%', @search, '%') OR " +
                "T.townshipname LIKE CONCAT('%', @search, '%') OR " +
                "D.divisionname LIKE CONCAT('%', @search, '%') " +
                "ORDER BY T.townshipcode LIMIT " + start + "," + pageDisplayLength;                     
    }
    else{
        query = "SELECT T.*,D.divisionname FROM Township AS T " +
               "INNER JOIN Division AS D ON T.divisionid=D.divisionid ORDER BY T.townshipcode LIMIT " + start + "," + pageDisplayLength;
    }
    List<Township> townshipList = getMultiRecords(query);
    return townshipList;
}

以下是getMultiRecords方法的基类：

protected List<T> getMultiRecords(String query){
    List<T> listResult = jdbcTemplate.query(query, new RowMapper<T>(){
        @Override 
        public T mapRow(ResultSet rs, int rowNum) throws SQLException {
            T entity = readRecord(rs);
            return entity;
        }
    });
    return listResult;
}

以下是我的BadSqlGrammarException详细信息。

Request processing failed; nested exception is org.springframework.jdbc.BadSqlGrammarException: StatementCallback; bad SQL grammar [SET @search = 'B'; SELECT T.*,D.divisionname FROM Township AS T INNER JOIN Division AS D ON T.divisionid=D.divisionid WHERE T.townshipcode LIKE CONCAT('%', @search, '%') OR T.townshipname LIKE CONCAT('%', @search, '%') OR D.divisionname LIKE CONCAT('%', @search, '%') ORDER BY T.townshipcode LIMIT 0,10]; nested exception is com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT T.*,D.divisionname FROM Township AS T INNER JOIN Division AS D ON T.divis' at line 1

请帮我找出问题所在。

Answer 1

我猜这个解析器对你在一个语句中使用的两个语句不满意。您应该使用parameter binding，而不是SET并将所有参数添加到String。如果不支持set语句，我不会感到惊讶。

你的陈述也错过了结束分号。由于您缺少确切/完整的错误消息，因此只能猜测。

Answer 2

尝试将搜索特定查询更改为命名参数。并调用方法适当的参数。

query =   "SELECT T.*,D.divisionname FROM Township AS T " +
                "INNER JOIN Division AS D ON T.divisionid=D.divisionid " +
                "WHERE T.townshipcode LIKE CONCAT('%', :search, '%') OR " +
                "T.townshipname LIKE CONCAT('%', :search, '%') OR " +
                "D.divisionname LIKE CONCAT('%', :search, '%') " +
                "ORDER BY T.townshipcode LIMIT " + start + "," + pageDisplayLength;  

Map<String, Object> queryParams = new HashMap<>();
queryParams.put("search", searchParameter);

更新方法代码以接受命名参数。

protected List<T> getMultiRecords(String query, Map<String,Object> namedParams){ 
    List<T> listResult = new ArrayList();
    if (namedParams != null && namedParams.size() > 0) {
        listResult = jdbcTemplate.query(query, namedParams ,new RowMapper<T>(){
            @Override 
            public T mapRow(ResultSet rs, int rowNum) throws SQLException {
                T entity = readRecord(rs);
                return entity;
            }
        });
    } else {
        listResult = jdbcTemplate.query(query ,new RowMapper<T>(){
            @Override 
            public T mapRow(ResultSet rs, int rowNum) throws SQLException {
                T entity = readRecord(rs);
                return entity;
            }
        });
    }
    return listResult;
}

MySQL查询正确的语法在JdbcTemplate中不起作用

2 个答案: