优化“不在”查询

Question

请帮助优化此查询：

SELECT ts.SiteId, COUNT(ts.SiteId) AS Count 
FROM ts 
WHERE ts.SiteId not in 
   (SELECT ts.SiteId FROM ts WHERE ts.uniqueid = 'xxx') 
GROUP BY ts.SiteId ORDER BY Count DESC

Answer 1

SELECT ts.SiteId, COUNT(ts.SiteId) AS Count, 
MAX(CASE WHEN ts.uniqueid = 'xxx' THEN 1 ELSE 0 END) As XXXUniqueID
FROM ts 
GROUP BY ts.SiteId
HAVING XXXUniqueID = 0
ORDER BY Count DESC

Answer 2

在SQL 2005 CTE中，它可能如下所示：

;
WITH 
e AS
(
    SELECT ts.SiteId FROM ts 
    EXCEPT
    SELECT ts.SiteId FROM ts WHERE ts.uniqueid = 'xxx'
)
SELECT e.SiteId, COUNT(e.SiteId) AS Count 
FROM e
GROUP BY e.SiteId ORDER BY Count DESC