我正在构建一个Android应用程序，当注册用户必须提供他们的信息，其中包括他们的个人资料图片时，应用程序然后将图像编码为Base64字符串并将其与其他所有其他信息一起添加到数组列表中提供，我的问题是将服务器端的Base64字符串解码为Image并将图像名称保存到数据库中，如果用户没有上传图像应该设置默认图像，我尝试了几种方法但是都失败了，如果我在我的JSON帖子中没有包含Base64图像字符串，应用程序运行平稳意味着我正在搞乱解码图像并设置它，如果我在浏览器中运行整个Php代码它完美地运行，所以卡住了，哪里手机出了问题？
如果提供图像，则执行此代码
if (imgPath !=null)
{
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 8;
final Bitmap bitmapOrg = BitmapFactory.decodeFile(imgPath, options);
ByteArrayOutputStream bao = new ByteArrayOutputStream();
bitmapOrg.compress(Bitmap.CompressFormat.JPEG, 90, bao);
byte [] ba = bao.toByteArray();
String profile_pic= Base64.encodeToString(ba, 0);
try {
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", username));
params.add(new BasicNameValuePair("password", password));
params.add(new BasicNameValuePair("fname", fname));
params.add(new BasicNameValuePair("lname", lname));
params.add(new BasicNameValuePair("email", email));
params.add(new BasicNameValuePair("city", city));
params.add(new BasicNameValuePair("nrc", nrc));
params.add(new BasicNameValuePair("dob", dob));
params.add(new BasicNameValuePair("cell", cell));
params.add(new BasicNameValuePair("profile", profile_pic));
如果没有提供图像，则执行以下代码：
try {
String profile_pic = null;
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", username));
params.add(new BasicNameValuePair("password", password));
params.add(new BasicNameValuePair("fname", fname));
params.add(new BasicNameValuePair("lname", lname));
params.add(new BasicNameValuePair("email", email));
params.add(new BasicNameValuePair("city", city));
params.add(new BasicNameValuePair("nrc", nrc));
params.add(new BasicNameValuePair("dob", dob));
params.add(new BasicNameValuePair("cell", cell));
params.add(new BasicNameValuePair("profile", profile_pic));
在我的服务器端，以下代码将在收到数据后执行：
if (!empty($_POST)) {
if(!empty($_POST['profile']) || $_POST['profile'] == null)
{
$image = $_POST['profile'];
$binary=base64_decode($image);
$source = imagecreatefromstring($binary);
}
if (empty($_POST['username']) || empty($_POST['password']))
{
// Create some data that will be the JSON response
$response["success"] = 0;
$response["message"] = "Please Make Sure All Fields Are filled";
die(json_encode($response));
}
$query = " SELECT 1 FROM users WHERE username = :user";
//now lets update what :user should be
$query_params = array(
':user' => $_POST['username']
);
try {
// These two statements run the query against your database table.
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error1. Please Try Again!";
die(json_encode($response));
}
$row = $stmt->fetch();
if ($row) {
$response["success"] = 0;
$response["message"] = "I'm sorry, this username is already in use";
die(json_encode($response));
}
$Destination = 'avatars';
if(!isset($_POST['profile']) ||
!is_uploaded_file($_POST['profile']['tmp_name']) ||
$_POST['profile'] == null )
{
$NewImageName= 'default.jpg';
move_uploaded_file($_POST['profile']['tmp_name'], "$Destination/$NewImageName");
}else{
$RandomNum = rand(0, 9999999999);
$ImageName = str_replace(' ','-',strtolower($_POST['profile']['name']));
$ImageType = $_POST['profile']['type'];
$ImageExt = substr($ImageName, strrpos($ImageName, '.'));
$ImageExt = str_replace('.','',$ImageExt);
$ImageName = preg_replace("/\.[^.\s]{3,4}$/", "", $ImageName);
$NewImageName = $ImageName.'-'.$RandomNum.'.'.$ImageExt;
move_uploaded_file($_POST['profile']['tmp_name'], "$Destination/$NewImageName");
}
$sql5="UPDATE users SET propic='$NewImageName' WHERE username = ':username'";
$sql6="INSERT INTO users (propic) VALUES ('$NewImageName') WHERE username = ':username'";
$query = "INSERT INTO users ( username,
fname,
lname,
password,
email,
city,
dob,
nrc,
cell,
propic)
VALUES ( :user,
:fnam,
:lnam,
:pass,
:emai,
:cit,
:do,
:nr,
:cel,
:NewImageName )";
//Again, we need to update our tokens with the actual data:
$query_params = array(
':user' => $_POST['username'],
':fnam' => $_POST['fname'],
':lnam' => $_POST['lname'] ,
':pass' => md5($_POST['password']),
':emai' => $_POST['email'],
':cit' => $_POST['city'],
':do' => $_POST['dob'],
':nr' => $_POST['nrc'],
':cel' => $_POST['cell'],
':NewImageName' =>$NewImageName);
//time to run our query, and create the user
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one:
$response["success"] = 0;
$response["message"] = "Database Error2. Please Try Again!";
die(json_encode($response));
}
$response["success"] = 1;
$response["message"] = "Username Successfully Added!";
echo json_encode($response);