如何显示特定记录及其父母(最多两个)?
import Cocoa
class HeartView: NSView {
var mouseLocation : NSPoint = NSZeroPoint
func drawObject(){
//Create an empty Bezier path
let aBezier : NSBezierPath = NSBezierPath()
aBezier.moveToPoint(CGPoint(x: 176.95,y: 44.90))
aBezier.curveToPoint(CGPoint(x: 166.71,y: 145.89),
controlPoint1: CGPoint(x: 76.63,y: 76.78),
controlPoint2: CGPoint(x: 82.59,y: 206.70))
aBezier.curveToPoint(CGPoint(x: 176.95,y: 44.90),
controlPoint1: CGPoint(x: 237.55,y: 224.76),
controlPoint2: CGPoint(x: 276.83,y: 95.98))
aBezier.closePath()
if (aBezier.containsPoint(NSMakePoint(mouseLocation.x, mouseLocation.y))){
NSColor.yellowColor().setFill()
NSColor.greenColor().setStroke()
} else {
NSColor.blueColor().setFill()
NSColor.orangeColor().setStroke()
}
aBezier.fill()
aBezier.lineWidth = 2.0
aBezier.stroke()
}
override func drawRect(dirtyRect: NSRect) {
super.drawRect(dirtyRect)
drawObject()
}
override func mouseDown(theEvent: NSEvent) {
mouseLocation.x = theEvent.locationInWindow.x
mouseLocation.y = theEvent.locationInWindow.y
self.setNeedsDisplayInRect(self.frame)
}
我不知道怎么做。以下查询不起作用。
Table:
+---------------+
| id | parentID |
+---------------+
| 1 | null |
| 2 | 1 |
| 3 | 1 |
| 4 | 2 |
| 5 | 2 |
| 6 | 2 |
+---------------+
The expected result:
Showing record with id 4 and his two parents
+---------------+
| id | parentID |
+---------------+
| 1 | null |
| 2 | 1 |
| 4 | 2 |
+---------------+
我对高级查询的了解很差。请帮助:)
答案 0 :(得分:0)
你需要CURSOR和LOOP。你将从孩子一直循环到根(直到parentId为NULL)。