Question

我有一系列位置和嵌套用户对象，如下所示：

[ 
  position: {
    title: Developer,
    user: { name: Albert }
    },
  position: {
    title: CEO,
    user: { name: Smith }
    }
]

如何使用Angularjs获取[user，user]数组？

Answer 1

假设这是伪代码（因为它缺少一些{和}，你需要变量名为Developer，Albert，CEO＆amp; Smith - I＆＃ 39;已经在工作示例中修复了这些）你可以使用Array.map：

var arr = [{ 
  Position0: {
    title: Developer,
    user: { name: Albert }
    },
 {
  Position1 : {
    title: CEO,
    user: { name: Smith }
    }
}];
var result = arr.map(function(val, idx) {
    return val["Position" + idx].user.name;
});

Working Example

Answer 2

我刚试过这段代码，并且有效......

var positions, users;

users = [];
positions = [
  {
    title: 'Developer',
    user: { name: 'Albert' }
  },
  {
    title: 'CEO',
    user: { name: 'Smith' }
  }
];


angular.forEach(positions, function(position) {
  users.push(position.user);
});

console.log(users);

Answer 3

使用angular.forEach()：

var arr1=[]
var arr=[ 
  position: {
    title: Developer,
    user: { name: Albert }
    },
  position: {
    title: CEO,
    user: { name: Smith }
    }
];
angular.forEach(arr,function(value,key){
   arr1[key]=value.position.user;
});
console.log(arr1);

Answer 4

首先，这件事不需要angularjs。

您可以这样做的方法是使用每个循环：

var users = [];
var positions = [{ 
  Position0: {
    title: 'Developer',
    user: { name: 'Albert' }
    },

  Position1 : {
    title: 'CEO',
    user: { name: 'Smith' }
    }
}] 
    for(var i =0; i< positions.length; i++){
        for(var j in positions[i]){ //used to loop on object properties
          if(positions[i].hasOwnProperty(j)){ //checking if the property is not inherited
             if(positions[i][j].user){ //checking if the property exist, then only will push it to array, so that array doesnot have undefined values
                users.push(positions[i][j].user);
             }
          }
        }
    }

用户数组将拥有用户。

Angularjs数组中嵌套对象的数组

4 个答案: