Question

我正在使用youtube api，我想申请分页但我不知道该怎么做我在谷歌上搜索，只获取我必须获取页面令牌的信息但我不知道如何获取页面令牌请帮我解决这个问题感谢。

    <?php

$htmlBody = <<<END
<form method="GET">
  <div>
    Search Term: <input type="search" id="q" name="q" placeholder="Enter Search Term">
  </div>
  <div>
    Max Results: <input type="number" id="maxResults" name="maxResults" min="1" max="50" step="1" value="25">
  </div>
  <input type="submit" value="Search">

</form>
END;

// This code will execute if the user entered a search query in the form
// and submitted the form. Otherwise, the page displays the form above.
if ($_GET['q'] && $_GET['maxResults']) {
  // Call set_include_path() as needed to point to your client library.
  require_once ($_SERVER["DOCUMENT_ROOT"].'/youtube/google-api-php-client/src/Google_Client.php');
  require_once ($_SERVER["DOCUMENT_ROOT"].'/youtube/google-api-php-client/src/contrib/Google_YouTubeService.php');

  /*
   * Set $DEVELOPER_KEY to the "API key" value from the "Access" tab of the
   * Google Developers Console <https://console.developers.google.com/>
   * Please ensure that you have enabled the YouTube Data API for your project.
   */
  $DEVELOPER_KEY = 'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX';

  $client = new Google_Client();
  $client->setDeveloperKey($DEVELOPER_KEY);

  // Define an object that will be used to make all API requests.
  $youtube = new Google_YoutubeService($client);

  try {
    // Call the search.list method to retrieve results matching the specified
    // query term.
    $searchResponse = $youtube->search->listSearch('id,snippet', array(
      'q' => $_GET['q'],
      'maxResults' => '10',
    ));

    $videos = '';
    $channels = '';
    $playlists = '';

    // Add each result to the appropriate list, and then display the lists of
    // matching videos, channels, and playlists.
    foreach ($searchResponse['items'] as $searchResult) {
      switch ($searchResult['id']['kind']) {
        case 'youtube#video':
          $videos .= sprintf('<a href=new/yt.php?videoid='.$searchResult['id']['videoId'].' target=_blank><li>%s (%s)</li>', $searchResult['snippet']['title'],
            $searchResult['id']['videoId']."   Watch This Video<br><img  src=' http://img.ytapi.com/vi/".$searchResult['id']['videoId']."/mqdefault.jpg' /></a>");
          break;
        case 'youtube#channel':
          $channels .= sprintf('<li>%s (%s)</li>',
              $searchResult['snippet']['title'], $searchResult['id']['channelId']);
          break;
        case 'youtube#playlist':
          $playlists .= sprintf('<li>%s (%s)</li>',
              $searchResult['snippet']['title'], $searchResult['id']['playlistId']);
          break;
      }
    }

    $htmlBody .= <<<END
    <h3>Videos</h3>
    <ul>$videos</ul>
    <h3>Channels</h3>
    <ul>$channels</ul>
    <h3>Playlists</h3>
    <ul>$playlists</ul>
END;
  } catch (Google_ServiceException $e) {
    $htmlBody .= sprintf('<p>A service error occurred: <code>%s</code></p>',
      htmlspecialchars($e->getMessage()));
  } catch (Google_Exception $e) {
    $htmlBody .= sprintf('<p>An client error occurred: <code>%s</code></p>',
      htmlspecialchars($e->getMessage()));
  }
  ?>
      <h1><a href="<?php echo $_SERVER['REQUEST_URI'] ?>/<?php echo $searchResponse['nextPageToken'] ?>">next</a></h1>

<?php
}
?>

<!doctype html>
<html>
  <head>
    <title>YouTube Search</title>
  </head>
  <body>
    <?=$htmlBody?>
  </body>
</html>

Answer 1

搜索响应将返回＆＃34; nextPageToken＆＃34;并且可能是＆＃34; prevPageToken＆＃34;可以与您的下一个请求一起传递（除了更改页面令牌之外，应该与当前请求相同）以获取不同的数据集。你用＆＃34; pageToken＆＃34;传递它。参数（不是代码在此处执行的URL路径的一部分）。因此，例如，您可以将搜索请求修改为如下所示：

<h1><a href="<?php echo $_SERVER['REQUEST_URI'] ?>?q=<?php echo $_GET['q']>&pageToken=<?php echo $searchResponse['nextPageToken'] ?>">next</a></h1>

然后，您显示搜索结果，然后显示您的＆＃34; next＆＃34;链接应该像这样修改：

 #include<stdio.h>
#include<conio.h>
#include<stdlib.h>

struct Node{
 int data;
 struct Node* next;
};
struct Node* head;  //global variable
int main(){
    head = NULL;  //empty list
    int n, i, x;
    printf("How many numbers would you like to enter");
    scanf("%d", &n);
    for(i=0; i<n; i++){
        printf("Enter the number you want to add to list:");
        scanf("%d", &x);
        Insert(x);
        Print();
    }
}


void Insert(int x){
Node* temp= (Node*)malloc(sizeof(struct Node)); //I get error here
temp->data = x;
//temp->next = NULL; //redundant
//if(head!= NULL){
temp->next = head;  //temp.next will point to null when head is null nd otherwise what head was pointing to
//}
head = temp;
}

void Print(){
    struct Node* temp1 = head;  //we dont want tomodify head so store it in atemp. bariable and then traverse
    while(temp1 != NULL){
         printf(" %d", temp1->data);
         temp1= temp1->next;
    }
    printf("\n");
}

如何在youtube搜索列表中应用分页..？

1 个答案: