Question

SELECT A.HOUR,A.ACTUAL_COUNT,B.EXPECTED_COUNT 
FROM (
    SELECT EXTRACT(HOUR FROM REPORT_INQUIRY_DT) HOUR ,COUNT(1) ACTUAL_COUNT
    FROM SBE_RPT_INQ_OUTPUT
    WHERE TO_CHAR(REPORT_INQUIRY_DT,'YYYY-MM-DD')='2015-04-19' 
    GROUP BY EXTRACT(HOUR FROM REPORT_INQUIRY_DT)
    ORDER BY EXTRACT(HOUR FROM REPORT_INQUIRY_DT)
) A
left outer JOIN (
    SELECT EXTRACT(HOUR FROM REPORT_INQUIRY_DT) AS HOUR,
        ROUND(COUNT(1)/4) EXPECTED_COUNT
    FROM (
        SELECT * 
        FROM SBE_RPT_INQ_OUTPUT
        WHERE TO_CHAR(REPORT_INQUIRY_DT,'YYYY-MM-DD')=TO_CHAR((SELECT SYSDATE -7 FROM DUAL),'YYYY-MM-DD')
        UNION ALL
        SELECT * 
        FROM SBE_RPT_INQ_OUTPUT
        WHERE TO_CHAR(REPORT_INQUIRY_DT,'YYYY-MM-DD')=TO_CHAR((SELECT SYSDATE -14 FROM DUAL),'YYYY-MM-DD')
        UNION ALL
        SELECT * 
        FROM SBE_RPT_INQ_OUTPUT
        WHERE TO_CHAR(REPORT_INQUIRY_DT,'YYYY-MM-DD')=TO_CHAR((SELECT SYSDATE -21 FROM DUAL),'YYYY-MM-DD')
        UNION ALL
        SELECT * 
        FROM SBE_RPT_INQ_OUTPUT
        WHERE TO_CHAR(REPORT_INQUIRY_DT,'YYYY-MM-DD')=TO_CHAR((SELECT SYSDATE -34 FROM DUAL),'YYYY-MM-DD') 
    ) A
    GROUP BY EXTRACT(HOUR FROM A.REPORT_INQUIRY_DT)
    ORDER BY EXTRACT(HOUR FROM A.REPORT_INQUIRY_DT) 
) B
ON A.HOUR=B.HOUR;

和我得到的答案。

hour Actual_Count Expect_count
7    2            0

我想显示所有小时交易，即使它不是null。

Answer 1

我在您的查询中看到了一些奇怪的内容，但是，如果没有任何要求说明，我只能假设它正是您想要提取的内容，除非您没有获取任何行缺少值的小时数。

因此，要获取缺失值，您可以尝试此查询：

with hours as (
        select rownum-1 as hour
        from dual
        connect by rownum <= 24
    )
select h.HOUR, count(*)
from hours h
    left join (
            select *
            from SBE_RPT_INQ_OUTPUT t 
            where t.REPORT_INQUIRY_DT >= (trunc(sysdate)-(34))
                and t.REPORT_INQUIRY_DT < trunc(sysdate)
        ) t
        on (
            mod(trunc(t.REPORT_INQUIRY_DT)-trunc(sysdate)) in (7,14,21,34)
            and hour = EXTRACT(HOUR FROM REPORT_INQUIRY_DT)
        )
group by h.HOUR

无论如何，你很难理解为什么你不想在0到6,8到13,15到20和22到33之间匹配前几天的事件。

<强>更新

要获取当天的小时数和过去4周的平均小时数，您可以使用此其他查询

with hours as (
        select rn, mod(EXTRACT(HOUR FROM systimestamp) + 24 - rn,24) as hour
        from (
                select rownum-1 as rn
                from dual
                connect by rownum <= 24
            )
    )
select sysdate, HOUR as hour, nvl(avg,0) as avg, nvl(current_count,0) as current_count
from hours h
    left join (
            select EXTRACT(HOUR FROM REPORT_INQUIRY_DT) as hour, 
                count(case when t.REPORT_INQUIRY_DT < trunc(sysdate) then 1 end)/(4*7) as avg,
                count(case when t.REPORT_INQUIRY_DT >= trunc(sysdate) then 1 end) as current_count
            from SBE_RPT_INQ_OUTPUT t 
            where t.REPORT_INQUIRY_DT >= (trunc(sysdate)-(4*7))
            group by EXTRACT(HOUR FROM REPORT_INQUIRY_DT)
        ) t using (hour)
order by rn

显示查询的所有行，甚至是空值

1 个答案: