Question

这是shell脚本代码，当我在centos 6.6中使用时，会收到两条错误信息....

./script12.bash: line 11: syntax error near unexpected token `$1'
./script12.bash: line 11: `case $1 in'

你能帮我找到错误吗？

#! /bin/bash
num=0
until [ "$num" -eq 30 ]
do
　　 echo -n "Please input a number here : "
　　 read num

　　 if [ "$num" -gt 30 ] ; then
　　　　echo "$num" is too big , try again.
　　　　echo
　　 elif [ "$num" -eq 30 ] ; then
　　　　echo BINGO !! you got it.
　　 else
　　　　echo "$num" is too small , try again.
　　　　echo
　　 fi
done

Answer 1

不确定你的脚本是如何包含奇怪的空白字符，十六进制编辑器显示ASCII码80个字符，这似乎混淆了bash。用普通空格（ASCII代码20）替换它们时，以下工作：

#!/bin/bash

num=0
until [ "$num" -eq 30 ]
do
    echo -n "Please input a number here : "
    read num

    if [ "$num" -gt 30 ] ; then
        echo "$num" is too big , try again.
        echo
    elif [ "$num" -eq 30 ] ; then
        echo BINGO !! you got it.
    else
        echo "$num" is too small , try again.
        echo
    fi
done

Centos 6.6 shell脚本 - 在意外令牌附近发生错误

1 个答案: