当我点击发送到mailto:admin@ikiyuzoniki.net的链接时,我收到此错误:
net:ERR_UNKNOWN_URL_SCHEME
我尝试添加if(url.startsWith("mailto:"))
条件,但它无效。
这是我的MyWebViewClient
方法:
public class MyWebViewClient extends WebViewClient {
@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
}
@Override
public void onPageFinished(WebView view, String url) {
view.setVisibility(View.VISIBLE);
final Animation fade = new AlphaAnimation(0.0f, 1.0f);
fade.setDuration(200);
view.startAnimation(fade);
view.setVisibility(View.VISIBLE);
}
}
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if(url.startsWith("mailto:")){
Intent intent = null;
try {
intent = Intent.parseUri(url, Intent.URI_INTENT_SCHEME);
} catch (URISyntaxException e) {
e.printStackTrace();
}
view.getContext().startActivity(intent);
}
else if (url.endsWith(".mp3")) {
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.parse(url), "audio/*");
startActivity(intent);
} else if (url.endsWith(".mp4") || url.endsWith(".3gp")) {
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.parse(url), "video/*");
startActivity(intent);
}
else {
return false;
}
view.reload();
return true;
}
这就是我在loadUrl
之前将该功能添加到我的网页视图中的方法:
...
mWebview.setWebViewClient(new MyWebViewClient());
...
答案 0 :(得分:7)
试试这个
if(url.startsWith("mailto:")){
MailTo mt = MailTo.parse(url);
Intent i = new Intent(Intent.ACTION_SEND);
i.setType("text/plain");
i.putExtra(Intent.EXTRA_EMAIL, new String[]{mt.getTo()});
i.putExtra(Intent.EXTRA_SUBJECT, mt.getSubject());
i.putExtra(Intent.EXTRA_CC, mt.getCc());
i.putExtra(Intent.EXTRA_TEXT, mt.getBody());
mContext.startActivity(i);
view.reload();
return true;
}
答案 1 :(得分:2)
出现此错误是因为WebView无法识别URL方案,例如,WebView通常会识别http和https,除了这些以外的任何其他字符,例如– intent://,market://,app: //,mail://等不会被webview识别,除非我们添加一个处理程序来处理这些url方案或禁用这些方案并仅加载http和https方案。
这是修复通用意图url方案的示例。
mWebView.setWebViewClient(new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
return loadUrl(view, url);
}
@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
super.onPageStarted(view, url, favicon);
}
@Override
public void onPageFinished(WebView view, String url) {
super.onPageFinished(view, url);
}
@Override
public void onReceivedError(WebView view, int errorCode, String description,String failingUrl) {
super.onReceivedError(view, errorCode, description, failingUrl);
//Log.d("Web Request Error", "");
showError(errorCode);
}
@TargetApi(Build.VERSION_CODES.M)
@Override
public void onReceivedError(WebView view, WebResourceRequest request, WebResourceError error) {
super.onReceivedError(view, request, error);
Log.d("WebResource error", "");
int errorCode = error.getErrorCode();
showError(errorCode);
}
});
private boolean loadUrl(WebView view, String url) {
if (url.startsWith("http:") || url.startsWith("https:")) {
view.loadUrl(url);
return false;
}
// Otherwise allow the OS to handle it
else if (url.startsWith("tel:")) {
Intent tel = new Intent(Intent.ACTION_DIAL, Uri.parse(url));
startActivity(tel);
return true;
} else if (url.toLowerCase().startsWith("mailto:")) {
MailTo mt = MailTo.parse(url);
Intent emailIntent = newEmailIntent(mt.getTo(), mt.getSubject(), mt.getBody(), mt.getCc());
startActivity(emailIntent);
return true;
}
return true;
}
答案 2 :(得分:1)
err_unknown_url_scheme android webview problem solved-这对我有用...他们的HTML网页还处理tel,mailto,sms和geo。
webview.setWebViewClient(new MyWebViewClient());
webview.loadUrl("file:///android_asset/demo.html");
}
class MyWebViewClient extends WebViewClient
{
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url)
{
if( URLUtil.isNetworkUrl(url) )
{
return false;
}
try {
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(url));
startActivity(intent);
}catch(ActivityNotFoundException e)
{
Log.e("AndroiRide",e.toString());
Toast.makeText(MainActivity.this,"No activity found",Toast.LENGTH_LONG).show();
}
return true;
}
@RequiresApi(Build.VERSION_CODES.N)
@Override
public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request)
{
String url=request.getUrl().toString();
if( URLUtil.isNetworkUrl(url) )
{
return false;
}
try {
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(url));
startActivity(intent);
}catch(ActivityNotFoundException e)
{
Log.e("AndroiRide",e.toString());
Toast.makeText(MainActivity.this,"No activity found",Toast.LENGTH_LONG).show();
}
return true;
}
}
}`