我目前正在尝试将通过我的对象创建的值放入文件中。我的程序输出工作正常,我在另一个类的方法中的计算工作。我只想将matrixApp的输出保存到文件中。我还显示了我的输出看起来没有尝试保存到文件。我采取的路线似乎没有用,有什么建议吗?
import java.io.BufferedOutputStream;
import java.io.DataOutputStream;
import java.io.FileOutputStream;
import java.util.Scanner;
public class MatrixApp {
public static void main(String[] args) {
int m, n, p, q;
Scanner input = new Scanner(System.in);
System.out.println("Enter the number of rows and columns of first matrix");
m = input.nextInt();
n = input.nextInt();
System.out.println("Enter the number of rows and columns of second matrix");
p = input.nextInt();
q = input.nextInt();
System.out.println("Enter the elements of first matrix");
int first[][] = new int[m][n];
for (int c = 0; c < m; c++)
for (int d = 0; d < n; d++)
first[c][d] = input.nextInt();
System.out.println("Enter the elements of second matrix");
int second[][] = new int[p][q];
for (int c = 0; c < p; c++)
for (int d = 0; d < q; d++)
second[c][d] = input.nextInt();
MatrixMult matrixApp = new MatrixMult(first, second, m, n, p, q);
//String filename = "data.txt";
//FileOutputStream fout = new FileOutputStream(filename);
//BufferedOutputStream bout = new BufferedOutputStream(fout);
//DataOutputStream dout = new DataOutputStream(bout);
//for (int i=0; i < matrixApp; i++){ <--- the problem is here and
//dout.writeInt(matrixApp[][]); getting the program to do all the
//} the outputs
}
}
MatrixMult类
public class MatrixMult{
public MatrixMult(int first[][], int second[][], int m, int n, int p, int q) {
doMatrixMultiply(first, second, m, n, p, q);
}
public void doMatrixMultiply(int first[][], int second[][], int m, int n, int p, int q) {
if (n != p)
System.out
.println("Matrices with entered orders can't be multiplied with each other.");
else {
int multiply[][] = new int[m][q];
int addition[][] = new int[m][q];
int transpose[][] = new int[m][q];
int transpose2[][] = new int[m][q];
int mult = 0;
int sum = 0;
int tran = 0;
for (int c = 0; c < m; c++) {
for (int d = 0; d < q; d++) {
for (int k = 0; k < p; k++) {
mult = mult + first[c][k] * second[k][d];
}
multiply[c][d] = mult;
mult = 0;
}
}
System.out.println("Product of entered matrices:-");
for (int c = 0; c < m; c++) {
for (int d = 0; d < q; d++)
System.out.print(multiply[c][d] + "\t");
System.out.print("\n");
}
for (int c = 0; c < m; c++) {
for (int d = 0; d < q; d++) {
for (int k = 0; k < p; k++) {
sum = first[c][d] + second[c][d];
}
addition[c][d] = sum;
sum = 0;
}
}
System.out.println("Sum of entered matrices:-");
for (int c = 0; c < m; c++) {
for (int d = 0; d < q; d++)
System.out.print(addition[c][d] + "\t");
System.out.print("\n");
}
int c;
int d;
for (c = 0; c < m; c++) {
for (d = 0; d < q; d++)
transpose[d][c] = first[c][d];
}
for (c = 0; c < m; c++) {
for (d = 0; d < q; d++)
transpose2[d][c] = second[c][d];
}
System.out.println("Transpose of first entered matrix:-");
for (c = 0; c < n; c++) {
for (d = 0; d < m; d++)
System.out.print(transpose[c][d] + "\t");
System.out.print("\n");
}
System.out.println("Transpose of second entered matrix:-");
for (c = 0; c < n; c++) {
for (d = 0; d < m; d++)
System.out.print(transpose2[c][d] + "\t");
System.out.print("\n");
}
}
}
matrixApp的输出是
输入矩阵的产品: -
1 -2 -4
-1 7 -18
7 1 5
输入矩阵的总和: -
4 0 -3
4 4 -5
2 -1 7
转置第一个输入的矩阵: -
2 1 1
-1 0 1
0 -3 2
第二个输入矩阵的转置: -
2 3 1
1 4 -2
-3 -2 5
答案 0 :(得分:2)
您没有关闭您的流 - 显式缓冲。所以一切都在内存中,你永远不会被冲到磁盘上。使用try-with-resources语句适当地关闭所有内容,即使抛出异常。:
try (FileOutputStream fout = new FileOutputStream(filename);
BufferedOutputStream bout = new BufferedOutputStream(fout);
DataOutputStream dout = new DataOutputStream(bout)) {
// Note: Body here is as per original question. It won't compile, but
// we don't know what was expected.
for (int i=0; i < matrixApp; i++){
dout.writeInt(matrixApp[][]);
}
}
答案 1 :(得分:1)
好像您要保存名为MatrixMult
的{{1}}对象。
为什么不序列化呢?
在matrixApp
中实施java.io.Serializable
,然后致电MatrixMult
。
修改强>
根据您的评论,这里有关于如何序列化/反序列化的simple example。
如果您不想使用序列化,
我只想将matrixApp的输出保存到文件中。
假设“输出”是dout.writeObject(matrixApp)
和first
矩阵,
second
将其放在带有ressource的for (int i=0; i < first.length; i++){
for(int j = 0; k < first[i].length; j++)
dout.writeInt(first[i][j]);
for (int i=0; i < second.length; i++){
for(int j = 0; k < second[i].length; j++)
dout.writeInt(second[i][j]);
中,如@JonSkeet所解释。