即使凭据正确，Spring-security也无法登录用户

时间：2015-04-24 16:08:25

标签： java hibernate jsp spring-mvc spring-security

任何人都可以指出我的错误。我一开始无法使用注册用户登录我认为是因为我正在加密密码但是即使现在我已经删除了编码，用户仍然无法使用明文密码登录？

这是我的web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>SgaWebApp</display-name>
<welcome-file-list>
    <welcome-file>login.jsp</welcome-file>
</welcome-file-list>
<servlet>
    <display-name>dispatcher</display-name>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:com/sga/app/xml/dispatcher-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
    <url-pattern>*.css</url-pattern>
</servlet-mapping>
<resource-ref>
    <res-ref-name>jdbc/springSgaDb</res-ref-name>
    <res-type>javax.sql.DataSource</res-type>
    <res-auth>Container</res-auth>
</resource-ref>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
            classpath:com/sga/app/xml/security-context.xml
            classpath:com/sga/app/xml/dao-context.xml
            classpath:com/sga/app/xml/service-context.xml
        </param-value>
</context-param>

<filter>
    <display-name>springSecurityFilterChain</display-name>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>
<session-config>
    <session-timeout>60</session-timeout>
</session-config>

我的login.jsp：

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"  "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<link href="${pageContext.request.contextPath}/static/css/main.css"
rel="stylesheet" type="text/css">
<title>SGA-login page</title>
</head>
<body onload='document.f.j_username.focus();'>
<div class="wrapper">
    <!-- Form -->
    <div class="login">
        <h2 class="customLoginFormHeader">Login with Username and
            Password</h2>

        <c:if test="${param.error != null}">
            <p class="errorCustomLogin">Login failed. Please try your
                username/password again.</p>
        </c:if>

        <form name='f'
            action='${pageContext.request.contextPath}/j_spring_security_check'
            method='POST' class="loginForm">
            <table>
                <tr class="loginFormTableRow">
                    <td class="tdCustomLogin">Username:</td>
                    <td><input type='text' name='j_username'
                        class="usernameInputCustomLogin"></td>
                </tr>
                <tr class="loginFormTableRow">
                    <td class="tdCustomLogin">Password:</td>
                    <td><input type='password' name='j_password'
                        class="passwordInputCustomLogin" /></td>
                </tr>
                <tr class="loginFormTableRow">
                    <td class="tdRememberMeHeader">Remember me:</td>
                    <td><input type="checkbox"
                        name='_spring_security_remember_me' checked="checked"
                        class="rememberMeCustomLogin" /></td>
                </tr>
                <tr class="loginFormTableRow">
                    <td colspan='2'><input type="submit" value="Login"
                        class="customLoginSubmitButton" /></td>
                </tr>
            </table>
        </form>
    </div>
</div>
</body>
</html>

我的security-context.xml：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

<security:authentication-manager>
    <security:authentication-provider>
        <security:jdbc-user-service
            data-source-ref="dataSource" id="jdbcUserService" />
    </security:authentication-provider>
</security:authentication-manager>
<security:http use-expressions="true">
    <security:logout logout-success-url="/login"
        invalidate-session="true" />
    <security:intercept-url pattern="/admin"
        access="hasRole('ROLE_ADMIN')" />
    <security:intercept-url pattern="/admin"
        access="permitAll" />
    <security:intercept-url pattern="/login"
        access="permitAll" />
    <security:intercept-url pattern="/" access="permitAll" />
    <security:intercept-url pattern="/static/**"
        access="permitAll" />
    <security:intercept-url pattern="/customloginform"
        access="permitAll" />
    <security:intercept-url pattern="/error"
        access="permitAll" />
    <security:intercept-url pattern="/register"
        access="permitAll" />
    <security:intercept-url pattern="/createaccount"
        access="permitAll" />
    <security:intercept-url pattern="/accountcreated"
        access="permitAll" />
    <security:intercept-url pattern="/contactus"
        access="permitAll" />
    <security:intercept-url pattern="/denied"
        access="permitAll" />
    <security:intercept-url pattern="/menu"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/roundanalysis"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/roundanalysiserrorpage"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/analysisoutcome"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/viewmystats"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/userstats"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/clubstats"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/allstats"
        access="isAuthenticated()" />
    <security:intercept-url pattern="/**" access="denyAll" />
    <security:form-login login-page="/customloginform"
        default-target-url="/menu" authentication-failure-url="/customloginform?error=true" />
    <security:access-denied-handler
        error-page="/denied" />
    <security:remember-me key="sgaAppKey"
        user-service-ref="jdbcUserService" />
</security:http>
<security:global-method-security
    secured-annotations="enabled"></security:global-method-security>

我的LoginDAO：

@Repository
@Component("usersDAO")
@Transactional
public class UsersDAO {

private NamedParameterJdbcTemplate jdbc;

@Autowired
private SessionFactory sessionFactory;

public Session session() {
    return sessionFactory.getCurrentSession();
}

@Transactional
public boolean createUser(UserBean user) {
    MapSqlParameterSource params = new MapSqlParameterSource();
    params.addValue("username", user.getUsername());
    params.addValue("email", user.getEmail());
    params.addValue("password", user.getPassword());
    params.addValue("forename", user.getForename());
    params.addValue("surname", user.getSurname());
    params.addValue("homeclub", user.getHomeclub());
    params.addValue("authority", user.getAuthority());
    return jdbc
            .update("insert into users (username, email, password, forename, surname, homeclub, authority) values (:username, :email, :password, :forename, :surname, :homeclub, :authority)",
                    params) == 1;
}

@Autowired
public void setDataSource(DataSource jdbc) {
    this.jdbc = new NamedParameterJdbcTemplate(jdbc);
}

public boolean exists(String username) {
    return jdbc.queryForObject(
            "select count(*) from users where username=:username",
            new MapSqlParameterSource("username", username), Integer.class) > 0;
}

public List<UserBean> getAllUsers() {
    return jdbc.query("select * from users",
            BeanPropertyRowMapper.newInstance(UserBean.class));
}

}

这是控制台输出：

DEBUG - Request is to process authentication
DEBUG - Authentication attempt using org.springframework.security.authentication.dao.DaoAuthenticationProvider
DEBUG - Executing prepared SQL query
DEBUG - Executing prepared SQL statement [select username,password,enabled from users where username = ?]
DEBUG - Fetching JDBC Connection from DataSource
DEBUG - Returning JDBC Connection to DataSource
DEBUG - Executing prepared SQL query
DEBUG - Executing prepared SQL statement [select username,authority from authorities where username = ?]
DEBUG - Fetching JDBC Connection from DataSource
DEBUG - Returning JDBC Connection to DataSource
DEBUG - User 'Harry12345' has no authorities and will be treated as 'not found'
DEBUG - User 'Harry12345' not found
DEBUG - Authentication request failed: org.springframework.security.authentication.BadCredentialsException: Bad credentials
DEBUG - Updated SecurityContextHolder to contain null Authentication
DEBUG - Delegating to authentication failure handler org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler@65d201b5
DEBUG - Interactive login attempt was unsuccessful.
DEBUG - Cancelling cookie
DEBUG - Redirecting to /customloginform?error=true
DEBUG - Redirecting to '/SgaWebApp/customloginform?error=true'

1 个答案:

答案 0 :(得分：1)

日志输出清楚地显示了问题：

DEBUG - User 'Harry12345' has no authorities and will be treated as 'not found'

所以，它找到了用户，但没有发现任何与他相关的权限。

默认<security:jdbc-user-service />期望至少有一个与每个用户关联的权限。这些权限应按37.1 User Schema中的定义表示。

如果您想要不同的用户和权限数据表示（例如，您的authority字段），则需要实现自定义UserDetailsService。

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